Answer:
25/324
Step-by-step explanation:
Make a table of possible products:
![\left[\begin{array}{ccccccc}&1&2&3&4&5&6\\1&1&2&3&4&5&6\\2&2&4&6&8&10&12\\3&3&6&9&12&15&18\\4&4&8&12&16&20&24\\5&5&10&15&20&25&30\\6&6&12&18&24&30&36\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccccc%7D%261%262%263%264%265%266%5C%5C1%261%262%263%264%265%266%5C%5C2%262%264%266%268%2610%2612%5C%5C3%263%266%269%2612%2615%2618%5C%5C4%264%268%2612%2616%2620%2624%5C%5C5%265%2610%2615%2620%2625%2630%5C%5C6%266%2612%2618%2624%2630%2636%5Cend%7Barray%7D%5Cright%5D)
Of the 36 results, 10 are greater than 15.
The probability the product is greater than 15 on a single roll is 10/36 = 5/18.
The probability the product is greater than 15 on two rolls is (5/18)² = 25/324.
Set each factor EQUAL to zero to find the zeroes (since it is not actually equal to zero, you will use an open circle when graphing and an open bracket when writing in interval notation).
x = 0 x-1 = 0 x + 4 = 0
x = 1 x = -4
Next, choose a value to the far left, between each of the zeroes, and to the far right to evaluate if it makes a true statement when input into the given inequality.
far left (I choose -5): -5(-5 - 1)(-5 + 4) > 0 → (-)(-)(-) > 0 → negative > 0 FALSE
- 4 to 0 (I choose -2): -2(-2 - 1)(-2 + 4) > 0 → (-)(-)(+) > 0 → positive > 0 TRUE
0 to 1 (I choose 0.5): .5(.5 - 1)(.5 + 4) > 0 → (+)(-)(+) > 0 → negative > 0 FALSE
far right (I choose 2): 2(2 - 1)(2 + 4) > 0 → (+)(+)(+) > 0 → positive > 0 TRUE
Answer: (-4, 0) U (1, ∞)
Answer:
No Solution.
Step-by-step explanation:
Equality equation:
— 2y – Зу +8 = 8 — 5у – 12 (Given)
-5y + 8 = -4 - 5y (distributive property of equality)
-5y = -12 - 5y (subtraction property of equality)
= -12 (addition property of equality)
when you add 5y on both sides it cancels the 5y out, it's no solution.
