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3 years ago

What is the y-intercept of the line y + 11 = –2(x + 1.5)? y-intercept =

Mathematics

1 answer:

Lana71 [14]3 years ago

6 0

y + 11 = –2(x + 1.5)

y=mx+b

multiply the bracket by -2

(-2)(x)=-2x

(-2)(1.5)=-3

y+11=-2x-3

move +11 to the other side

sign changes from +11 to -11

y+11-11=-2x-3-11

y=-2x-14

m is also the slope

b= y-intercept

Answer:

y-intercept=-14

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Solve x2 + 18x – 19 = 0 by completing the square.

OlgaM077 [116]

Answer:

x = 1, x = -19

Step-by-step explanation:

1) factorise

(x−1)(x+19)=0

2) equal to 0

x−1=0 or x+19=0

x=1 or x=−19

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2 years ago

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Find the equation of a line with a slope of -4 that passes through the point (-3, 8).

Nata [24]

Answer:

The equation of line is y = -4x -4.

Step-by-step explanation:

Given that:

Slope of the line = -4

Line passes through the point ( -3, 8)

The general equation of line is given by;

y - y1 =m(x-x1)

Putting the point and slope in equation

y - 8 = -4(x - (-3))

y - 8 = -4(x+3)

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y = -4x -4

Hence,

The equation of line is y = -4x -4.

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3 years ago

Which table represents a linear function?

Vesna [10]

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3 0

3 years ago

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I have 200 coins to put into 4 bags I put the coins into each bag so that each bag has 2 mote coins than the one before How many

Allushta [10]

First bag has 47 coins and second bag has 49 coins and third bag has 51 coins and fourth bag has 53 coins

Solution:

Given that,

Total number of coins = 200

Number of bags = 4

I put the coins into each bag so that each bag has 2 more coins than the one before

Therefore,

Each bag has 2 more coins than the one before. Based on this we can say,

Let "x" be the number of coins put in first bag

Then, x + 2 is the number of coins put in second bag

Then, x + 4 is the number of coins put in third bag

Then, x + 6 is the number of coins put in fourth bag

We know that,

Total number of coins = 200

$x + x + 2 + x + 4 + x + 6 = 200\\\\4x + 12 = 200\\\\4x = 200-12\\\\4x = 188\\\\x = 47$

Thus,

Coins put in first bag = x = 47

Coins put in second bag = x + 2 = 47 + 2 = 49

Coins put in third bag = x + 4 = 47 + 4 = 51

Coins put in fourth bag = x + 6 = 47 + 6 = 53

Thus number of coins in each bag are found

4 0

3 years ago

How many milliequivalents of sodium chloride are contained with 3 L of normal saline?

AVprozaik [17]

Answer:

466mEq

Step-by-step explanation:

First, we need to know the concentration of NaCl in a normal saline solution, this is by definition 0.9%, meaning we have 0.9g of NaCl per 100ml of solution, we want to know how much NaCl we have in 3L (3000ml):

$3000ml*\frac{0.9g}{100ml}=27g=27000mg$

So, we have 27000mg in 3L of normal saline solution.

Now, acording to our milliequivalent (mEq) equation ( $mEq=\frac{mg}{pE}$ ) where pE is de molecular mass of NaCl divided by their charges, in this case 1:

$pE= \frac{23+35}{1}=\frac{58}{1} = 58$

Finally we substitute in the mEq formula:

$mEq=\frac{mg}{pE}=\frac{27000}{58}=466mEq$

I hope you find this information useful! Good luck!

4 0

3 years ago