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olganol [36]
2 years ago
7

The inflation of airbags is due to the breakdown of a single chemical substance into two separate substances. Two molecules of s

odium azide (NaN3) break down into sodium (Na) and nitrogen gas (N2) during the reaction. How many sodium (Na) atoms are produced in the reaction?
a) 1 Na atom
b)2 Na atoms
c)3 Na atoms
Chemistry
1 answer:
grandymaker [24]2 years ago
7 0
The answer is B 2 Na atoms
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What type of reaction always takes one large molecule and breaks it down into its smaller pieces?
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Answer:

The answer to your question is the letter D. a decomposition reaction

Explanation:

This is a brief description of the main chemical reactions.

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c) A combustion reaction is when an organic molecule reacts with oxygen to form carbon dioxide and water.

d) A decomposition reaction is when one reactant splits to form two or more products.

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What does the principle of faunal succession state?
svetoff [14.1K]

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Explanation:

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3 0
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One of the compounds used to increase the octane rating of gasoline is toluene (pictured). Suppose 43.3 mL of toluene (d = 0.867
Thepotemich [5.8K]

<u>Answer:</u>

(A)

Density = Mass / Volume

So  

Mass = Density × Volume

= 0.867 g/mL \times 43.3mL = 37.5411 g Toluene

1C_6 H_5 CH_3  + 9 O_2  > 7 CO_2  + 4 H_2 O

Mole ratio of toluene : Oxygen is 1 : 9

$37.5411 g \text { Toluene } \times \frac{1 \text {mol} \text {toluene}}{92 g \text { toluene}} \times \frac{9 {mol} O_{2}}{1 \text {mol} \text { toluene }} \times \frac{32 g O_{2}}{1 {mol} O_{2}}=117 g O_{2}(\text {Answer})$

(B)

1 mole of Toluene produces 7 moles of CO_2 gas and 4 moles of H_2 O Vapour

So the mole ratio is 1 : 11

37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene }} \times \frac{11 \mathrm{mol} \text { gas }}{1 \text { mol toluene }} $$\\\\=4.49 \text { mol gaseous products (Answer) } $

(C)

1mole contains 6.022\times10^{23} molecules

37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene}} \times \frac{4 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \text { toluene }} \times \frac{6.022 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}} $\\\\$=9.82 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O} \text { (Answer) } $

6 0
3 years ago
13??? pls also explain how u do it
Lady_Fox [76]

Answer:

d. it has a high boiling point

Explanation:

all ionic compounds with ionic bonds have high boiling points

7 0
3 years ago
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Fofino [41]

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3 0
3 years ago
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