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sesenic [268]
3 years ago
6

There are 81 amino acid residues in the precursor molecule of bovine insulin. What is the least number of bases that must be in

the DNA chain that codes for this molecule?
Chemistry
2 answers:
Usimov [2.4K]3 years ago
8 0
If you count the methionine expressed for the start codon as part of the precursor protein, then (81+1)*3. (The start codon is expressed, but the stop codon isn't.) 
Andreyy893 years ago
5 0

Answer:

246 amino bases

Explanation:

An amino acid is coded by three bases. However, in a DNA molecule, there is coding that takes place. In DNA replication, the start and stop codons are not expressed during the formation of the double helix. Hence, an extra amino acid will be needed. In fact, this can be expressed mathematically like this:

Number of bases = (n+1) * 3

where n is the number of amino acid residues. Therefore, taking 81 amino acid residues yields:

                 N = (81+ 1) * 3\\246

Therefore, the least number of bases needed will be 246

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1 year ago
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7 0
3 years ago
A 100.0 ml sample of 0.10 m ca(oh)2 is titrated with 0.10 m hbr. determine the ph of the solution after the addition of 400.0 ml
WINSTONCH [101]
The balanced equation for the reaction is as follows;
Ca(OH)₂ + 2HBr --> CaBr₂ + 2H₂O
stoichiometry of Ca(OH)₂ to HBr is 1:2
number of Ca(OH)₂ moles reacted - 0.10 mol/L x 0.1000 L = 0.010 mol
Number of HBr moles added - 0.10 mol/L x 0.4000 = 0.040 mol 
1 mol of Ca(OH)₂ needs 2 mol of HBr for neutralisation
therefore 0.010 mol of Ca(OH)₂  needs - 0.010 x 2 = 0.020 mol of HBr to be neutralised
but 0.040 mol of HBr has been added therefore number of moles of HBr in excess - 0.040 - 0.020 = 0.020 mol 
then pH of the medium can be calculated using the excess H⁺ ions
HBr is a strong acid therefore complete ionization
[HBr] = [H⁺]
[H⁺] = 0.020 mol / (100.0 + 400.0 mL)
      = 0.020 mol / 0.5 L 
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pH = -log[H⁺] 
pH = - log [0.040 M]
pH = 1.40
pH of the medium is 1.40
8 0
3 years ago
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