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sesenic [268]
3 years ago
6

There are 81 amino acid residues in the precursor molecule of bovine insulin. What is the least number of bases that must be in

the DNA chain that codes for this molecule?
Chemistry
2 answers:
Usimov [2.4K]3 years ago
8 0
If you count the methionine expressed for the start codon as part of the precursor protein, then (81+1)*3. (The start codon is expressed, but the stop codon isn't.) 
Andreyy893 years ago
5 0

Answer:

246 amino bases

Explanation:

An amino acid is coded by three bases. However, in a DNA molecule, there is coding that takes place. In DNA replication, the start and stop codons are not expressed during the formation of the double helix. Hence, an extra amino acid will be needed. In fact, this can be expressed mathematically like this:

Number of bases = (n+1) * 3

where n is the number of amino acid residues. Therefore, taking 81 amino acid residues yields:

                 N = (81+ 1) * 3\\246

Therefore, the least number of bases needed will be 246

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In metallic bonds, electrons are referred to as electrons.​
GrogVix [38]

Answer:

Metallic bonding may be described as the sharing of free electrons among a lattice of positively charged metal ions. The structure of metallic bonds is very different from that of covalent and ionic bonds. ... In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize.

5 0
3 years ago
What type of substance is always made up of a single type if atom
Damm [24]

Answer:

An Element

Explanation:

An Element is made up of only one type of atom (Gold, Silver, etc.)

Hope this helps!

4 0
3 years ago
Which subatomic particle determines the identity of an atom
Gelneren [198K]

The Protons determine the identity.

6 0
3 years ago
URGENT!!! What is the concentration in moles per litre of a solution that contains 7.68 g of H2SO4 in 150.0 mL of water?
hichkok12 [17]

Answer: 0.5225 mcl/l

Explanation:

5 0
3 years ago
A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

c_1 = specific heat of water = 4186 J/(kg.K)

m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0
3 years ago
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