If you count the methionine expressed for the start codon as part of the precursor protein, then (81+1)*3. (The start codon is expressed, but the stop codon isn't.)
An amino acid is coded by three bases. However, in a DNA molecule, there is coding that takes place. In DNA replication, the start and stop codons are not expressed during the formation of the double helix. Hence, an extra amino acid will be needed. In fact, this can be expressed mathematically like this:
where n is the number of amino acid residues. Therefore, taking 81 amino acid residues yields:
N =
Therefore, the least number of bases needed will be 246
Well if you go to Quiz-let it gives the answer the mass of a mole of compound is determined by adding the atomic masses of the atoms making up the molecules
