Answer:
1. succession
2. exponential growth
Explanation:
1. Ecological succession is how biological communities change, re-structure and re-assemble over time, usually after some change or disturbance, or occupation of a new habitat. Ecological succession usually starts with a very simplistic structure, with some founder species that begin, then over time (it could be 10 years, it could be millions of years), the population grows in complexity and develops.
2. Exponential growth refers to a specific pattern of growth that occurs when resources are not limited. This pattern is when the size of the population is always increasing at a greater and greater rate. The best example is in bacteria. When they are in favourable conditions, the cells keep dividing, doubling every day, leading to exponential growth until nutrients become limited and growth slows.
Be, B, C, N (going from smallest to biggest)
Answer:
See explanation
Explanation:
All the substances in the mixture; sodium chloride ,lead II oxide and iron filings are solids.
The first step is to use a magnet to separate the iron fillings which is a magnetizable material.
The remaining part of the mixture is now dissolved in water. Lead II oxide is insoluble in water while sodium chloride is very soluble in water hence a filtrate and a residue are obtained.
The residue is lead II oxide which can be dried to recover the solid. The filtrate contains sodium chloride which is recovered by evaporating the solution to dryness.
Answer:- 335 kcal of heat energy is produced.
Solution:- The balanced equation for the combustion of glucose in presence of oxygen to give carbon dioxide and water is:

From given info, 2803 kJ of heat is released bu the combustion of 1 mol of glucose. We need to calculate the energy produced when 3.00 moles of oxygen react with excess of glucose.
We could solve this using dimensional analysis as:

= 1401.5 kJ
Now, let's convert kJ to kcal.
We know that, 1kcal = 4.184kJ
So, 
= 335 kcal
Hence, 335 kcal of heat energy is produced by the use of 3.00 moles of oxygen gas.
Answer:
The three statements are true
Explanation:
For the reaction:
I₂O₅(s) + 5CO(g) → I₂(s) + 5CO₂(g)
State oxidation of iodine in I₂O₅ is:
5 O²⁻ = 10⁻
As you have 2 I and the molecule has no charge, <em>oxidation state of I is +5</em>.
The carbon in CO has an oxidation state of +2 and in CO₂ is +4. That means <em>the carbon is oxidized</em>
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An oxidizing agent is a substance that produce the oxidation of the agent that reacts with this one. CO is oxidized because of I₂O₅ is producing its oxidation being <em>the oxidizing agent</em>
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Thus,<em> the three statements are true</em>.