Create a system of linear equations that when solved algebraically, prove to have no solution.
2 answers:
Basically, you just need to make them have the same slope, but a different y - intercept. That means they'll never intersect, so will have no solution.
Say one equation is
y = 3x + 5
That means the other can be something like
y = 3x + 6
Right? Because if
3x + 5 = 3x + 6
and you subtract 3x from both sides
5 = 6
which can't be true.
The answer is y=3x+7 and y=3x+4
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Answer:
x = 47
Step-by-step explanation:
Every triangle's interior angles add up to 180°.
Let's make an equation.
x + 102 + 31 = 180
x + 133 = 180
x = 47
5 can go into 20 numbers between 1-100 and 8 can go into 12 numbers between 1-100
Answer:
x<4.5
Step-by-step explanation:
y
=(x-2)^2 +2 {x<4.5}
add the power and then divide by 2 you get 4.5
Answer:
The work is on the picture
sorry was not letting write the work here
Step-by-step explanation:
parallel lines or skew lines
Parallel lines are in Same plane or Coplanar but donot intersect each other. Skew lines lie in same plane but don't intersect each other.
