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2 years ago

Create a system of linear equations that when solved algebraically, prove to have no solution.

2 answers:

8 0

Basically, you just need to make them have the same slope, but a different y - intercept. That means they'll never intersect, so will have no solution.

Say one equation is

y = 3x + 5

That means the other can be something like

y = 3x + 6

Right? Because if

3x + 5 = 3x + 6

and you subtract 3x from both sides

5 = 6

which can't be true.

Natalija [7]2 years ago

7 0

The answer is y=3x+7 and y=3x+4

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2 years ago

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Find dy /dx of x² - 2x + 5 - 6x

BaLLatris [955]

Answer:

Step-by-step explanation:

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3 years ago

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Answer:first one is 38.67 and the second one is 12

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3 years ago

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Find the sale pice is the original price is $82 and discount is 10%

Tpy6a [65]

First you should find the discount so you can say:
10/100 = ?/82
so ? is your discount and ? is equal to:
? = 82*10/100 = 8.2
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I hope this is helpful
have a nice day

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3 years ago

What is three less than the product of four and the difference of a number and five

lilavasa [31]

Answer: 3-4n-5

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3 years ago