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maria [59]
2 years ago
9

Create a system of linear equations that when solved algebraically, prove to have no solution.

Mathematics
2 answers:
sweet [91]2 years ago
8 0

Basically, you just need to make them have the same slope, but a different y - intercept. That means they'll never intersect, so will have no solution.

Say one equation is

y = 3x + 5

That means the other can be something like

y = 3x + 6

Right? Because if

3x + 5 = 3x + 6

and you subtract 3x from both sides

5 = 6

which can't be true.

Natalija [7]2 years ago
7 0
The answer is y=3x+7 and y=3x+4
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telo118 [61]

Answer:

1. T

2. O

3. L

4. C

5.B

6.H

Step-by-step explanation:

8 0
2 years ago
I just need help with 6c. If you can, please explain how you got the answer.​
vagabundo [1.1K]

she could do multiplication AND division

3 0
3 years ago
Kianna started her homework at 4:30 pm. She finished at 5:05 pm. How many SECONDS did it take her to finish her homework? *
lozanna [386]

Answer:

2100 second

Step-by-step explanation:

4:30 pm to minutes

4 × 60 + 30 = 240 + 30

= 270 minutes

5:05 to minutes

5 × 60 + 5 = 300 + 5

= 305

4:30 to 5:05

305 - 270

= 35 minutes

35 minutes to second

35 × 60

= 2100 second

6 0
3 years ago
Read 2 more answers
If x=-3, then the solution of the equation 2x+6 is ?
Vlada [557]

Hello!

if x = -3, just substitute it for x (replace the x with -3)

2(-3) + 6 = 0

2 * -3 = -6

-6 + 6 = 0

I hope this helps, and have a nice day!

6 0
3 years ago
Part a at what speed v should an archerfish spit the water to shoot down an insect floating on the water surface located at a di
loris [4]
3.01 m/s  
This is a simple projectile calculation. What we want is a vertical velocity such that the time the droplet spends going up and going back down to the surface exactly matches the time the droplet takes to travel horizontally 0.800 meters. The time the droplet spends in the air will is:
 V*sqrt(3)/2 ; Vertical velocity.
 (V*sqrt(3)/2)/9.8 ; Time until droplet reaches maximum height
 (V*sqrt(3))/9.8 ; Double that time for droplet to fall back to the surface.
 
 The droplet's horizontal velocity will be:
 V/2.
 
 So the total distance the droplet travels will be:
 d = (V*sqrt(3))/9.8 * V/2
 d = V^2*sqrt(3)/19.6
 
 Let's substitute the desired distance and solve for V
 d = V^2*sqrt(3)/19.6
 0.8 = V^2*sqrt(3)/19.6
 15.68 = V^2*sqrt(3)
 15.68/sqrt(3) = V^2
 15.68/1.732050808 = V^2
 3.008795809 = V 
 So after rounding to 3 significant figures, the archerfish needs to spit the water at a velocity of 3.01 m/s 
 Let's verify that answer.
 Vertical velocity: 3.01 * sin(60) = 3.01 * 0.866025404 = 2.606736465
 Time of flight = 2.606736465 * 2 / 9.8 = 0.531987034 seconds. 
 Horizontal velocity: 3.01 * cos(60) = 3.01 * 0.5 =
8 0
3 years ago
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