The domain of this, assuming it's a function, is all real numbers such that x does not equal zero or negative ten.
In interval notation, this is (-∞, -10) U (-10, 0) U (0, <span>∞).
In set builder notation, this is {x | x </span>≠ -10, x <span>≠ 0}.
These inputs are excluded from the domain because they would otherwise allow division by zero. Try plugging in one of the restricted inputs. You'll see that it does not work! On a graph of this </span>function, you will see vertical asymptotes.
<span>object-oriented programming languages</span>
Answer:
a=4 , b=1
Explanation:
I'm not a computer science major at all but I think I can help you with this code.
Our program wants us to add 2 to a get new a value while also subtracting 1 from b value to obtain new b value. We we want to for for as long b is not 0 and a/b is nonnegative.
One round we get:
New a=0+2=2
New b=3-1=2
Let's see if we can go another round:
New a=2+2=4
New b=2-1=1
We can't go another round because b would be negative while a is positive which would make a/b negative. So our loop stops at this 2nd round.
a=4 , b=1
Other notes:
2nd choice makes no sense because a is always going to increase because of the addition on a and b was going to decrease because of the subtraction on it.
Third choice makes no sense because a/b doesn't even exist.
Fourth choice a/b is negative not nonnegative.
Answer:
c it reduces errors
Explanation:
Instead of Mrs.Patel doing it she has an online program made for checks to do it for her.