Question

g Q3 [20 points] Suppose that your average heart rate is 72. The average heart rate in your class is 82 and the variance is 25. a[10 points] What percent of the class has a lower heart rate

Answer 1

Answer:

2.28% of the class has a lower heart rate

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation(which is the square root of the variance) $\sigma$, the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 82, \sigma = \sqrt{25} = 5$

What percent of the class has a lower heart rate

Lower than 72, which is the pvalue of Z when X = 72.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{72 - 82}{5}$

$Z = -2$

$Z = -2$ has a pvalue of 0.0228

2.28% of the class has a lower heart rate