Question

A 92-kg receiver running at 8 m/s catches a pass across the middle and is immediately brought to a stop during a collision with a safety that lasts 0.6 seconds. What was the magnitude of force needed to stop the receiver

Answer 1

Answer: $1200\ N$

Explanation:

Given

Mass of receiver $m=92\ kg$

Running at a speed of $v=8\ m/s$

time taken to stop $t=0.6\ s$

We know, impulse imparted is given by

$\Rightarrow F\cdot dt=m\Delta v\\\Rightarrow F(0.6)=90(8-0)\\\\\Rightarrow F=\dfrac{90\times 8}{0.6}\\\\\Rightarrow F=1200\ N$

Thus, 1200 N is needed to stop the receiver.