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rusak2 [61]
3 years ago
15

A 92-kg receiver running at 8 m/s catches a pass across the middle and is immediately brought to a stop during a collision with

a safety that lasts 0.6 seconds. What was the magnitude of force needed to stop the receiver
Physics
1 answer:
sammy [17]3 years ago
7 0

Answer: 1200\ N

Explanation:

Given

Mass of receiver m=92\ kg

Running at a speed of v=8\ m/s

time taken to stop t=0.6\ s

We know, impulse imparted is given by

\Rightarrow F\cdot dt=m\Delta v\\\Rightarrow F(0.6)=90(8-0)\\\\\Rightarrow F=\dfrac{90\times 8}{0.6}\\\\\Rightarrow F=1200\ N

Thus, 1200 N is needed to stop the receiver.

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3 years ago
One hundred turns of insulated copper wire are wrapped into a circular coil of crosssectional area 1.20⇥103 m2. The two ends of
arsen [322]

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236.3  x 10^-^3 C

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According to Faraday's law, the induced emf is given by,

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The current given by resistance and induced emf as

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By converting the current to differential form(the time derivative of charge), we get

\frac{dq}{dt}=  -NdΦ/dtR

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5 0
3 years ago
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