Answer:
high tension: 4.2 × 1.5 = 6.3 cm/s
medium tension: 2.8 ×1.5 = 4.2 cm/s
low tension: 0.8 × 1.5 = 1.2 cm/s
Explanation: Given Settings:
amplitude: 0.75 cm
damping: zero
Using
Speed = frequency ×wavelength
Where
Wavelength = 0.75 × 2 = 1.5 cm
Therefore:
high tension: 4.2 × 1.5 = 6.3 cm/s
medium tension: 2.8 ×1.5 = 4.2 cm/s
low tension: 0.8 × 1.5 = 1.2 cm/s
Choice c) could represent the third step of inquiry.
Explanation:
Inquiry based learning is organized into inquiry phases.
The five general inquiry phase are
Orientation, conceptualisation, investigation, conclusion and discussion.
The investigation phase can be further divided into experimentation phase.
When Andrew washes three separate loads of dirty laundry ,one on hot setting,one one warm setting and one on cold setting , he is experimenting to collect data and interpreting it.
Only if he investigates will he know, which process will be suitable for doling out cleanest clothes.
Explanation:
First, find the velocity of the projectile needed to reach a height h when fired straight up.
Given:
Δy = h
v = 0
a = -g
Find: v₀
v² = v₀² + 2aΔy
(0)² = v₀² + 2(-g)(h)
v₀ = √(2gh)
Now find the height reached if the projectile is launched at a 45° angle.
Given:
v₀ = √(2gh) sin 45° = √(2gh) / √2 = √(gh)
v = 0
a = -g
Find: Δy
v² = v₀² + 2aΔy
(0)² = √(gh)² + 2(-g)Δy
2gΔy = gh
Δy = h/2
Answer:
A) I = Io 0.578, B) he light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter
Explanation:
A) Light passing through a polarizer must comply with the / bad law
I = Io cos2 tea
Where is at the angle of the polarizer and incident light
I = Io cos2 45
I = Io 0.578
Therefore the beam intensity is 0.578 of the incident intensity
.B) the light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter
