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Aloiza [94]
3 years ago
7

3. An object thrown vertically upwards reached a maximum height of 5.0 m. Calculate:

Physics
1 answer:
mr Goodwill [35]3 years ago
7 0

Answer:

Correct answer:  V₀ = 9.9 m/s

Explanation:

The subject is a vertical upward shot.

We will use the following formula:

V₀² = 2 · g · h  =>  V₀ = √2 · g · h ,  where V₀ is initial velocity

V₀ = √2 · 9.81 · 5 = √ 10 · 9.81 = √98.1 = 9.9 m/s

V₀ = 9.9 m/s

God is with you!!!

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Answer:

(a). The frequency of this standing wave is 0.782 kHz.

(b). The frequency of the fundamental standing wave in the air is 1.563 kHz.

Explanation:

Given that,

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Put the value into the formula

f_{1}=\dfrac{344}{4\times0.11}

f_{1}=781.81\ Hz

f_{1}=0.782\ kHz

(b). If the test tube is half filled with water

When the tube is half filled the effective length of the tube is halved

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Using formula of fundamental frequency of the fundamental standing wave in the air

f_{1}=\dfrac{v}{4(\dfrac{L}{2})}

Put the value into the formula

f_{1}=\dfrac{344}{4\times\dfrac{0.11}{2}}

f_{1}=1563.63\ Hz

f_{1}=1.563\ kHz

Hence, (a). The frequency of this standing wave is 0.782 kHz.

(b). The frequency of the fundamental standing wave in the air is 1.563 kHz.

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