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Aloiza [94]
3 years ago
7

3. An object thrown vertically upwards reached a maximum height of 5.0 m. Calculate:

Physics
1 answer:
mr Goodwill [35]3 years ago
7 0

Answer:

Correct answer:  V₀ = 9.9 m/s

Explanation:

The subject is a vertical upward shot.

We will use the following formula:

V₀² = 2 · g · h  =>  V₀ = √2 · g · h ,  where V₀ is initial velocity

V₀ = √2 · 9.81 · 5 = √ 10 · 9.81 = √98.1 = 9.9 m/s

V₀ = 9.9 m/s

God is with you!!!

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A light-rail commuter train accelerates at a rate of 1.35 m/s2. How long does it take to reach its top speed of 80.0 km/h, start
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Answer:

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Acceleration = a = 1.35 m/s²

Final velocity = v = 80 km/h = 80\frac{1000}{3600}=22.22\ m/s

Initial velocity = u = 0

Equation of motion

v=u+at\\\Rightarrow 22.22=0+1.35t\\\Rightarrow t=\frac{22.22}{1.35}=16.46\ s

Time taken to accelerate to top speed is 16.46 seconds.

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Initial velocity = u = 80 km/h= 80\frac{1000}{3600}=22.22\ m/s

Final velocity = v = 0

v=u+at\\\Rightarrow 0=22.22-1.65t\\\Rightarrow t=\frac{22.22}{1.65}=13.46\ s

Time taken to stop the train from top speed is 13.46 seconds

Initial velocity = u = 80 km/h= 80\frac{1000}{3600}=22.22\ m/s

Time taken = t = 8.3 s

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v=u+at\\\Rightarrow 0=22.22+a8.3\\\Rightarrow a=\frac{-22.22}{8.3}=-2.67\ m/s^2

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