A graph of velocity versus time (velocity displayed in m/s and time in seconds) displays a
1 answer:
Answer: acceleration is 2m/s^2
initial velocity is 4m/s
Explanation:
Since slope is rise/ run in this graph it will be change in velocity/ change and time. Therefore the slope of the graph will tell you the acceleration is 2m/s^2. The y intercepts is the velocity then time is 0, therefore the initial velocity is 4 m/s
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Answer:
<em>1,378.9ms² </em>
Explanation:
Given the following
Distance S = 70.6m
Time t = 0.32secs
Initial velocity = 0m/s
Required
Acceleration
Using the equation of motion
S = ut+1/2at²
Substitute
70.6 = 0+1/2a(0.32)²
70.6 = 0.0512a
a = 70.6/0.0512
a = 1,378.9
<em>Hence the acceleration is 1,378.9ms² </em>
