1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lapo4ka [179]
3 years ago
6

A graph of velocity versus time (velocity displayed in m/s and time in seconds) displays a

Physics
1 answer:
xxMikexx [17]3 years ago
5 0

Answer: acceleration is 2m/s^2

initial velocity is 4m/s

Explanation:

Since slope is rise/ run in this graph it will be change in velocity/ change and time. Therefore the slope of the graph will tell you the acceleration is 2m/s^2. The y intercepts is the velocity then time is 0, therefore the initial velocity is 4 m/s

You might be interested in
Cells are the basic building block that makes up all living things. Cells are microscopic. What does this mean?
Archy [21]

Answer:

microscopic means that they are very very tiny, you cannot see them with the human eye, you have to use a tool like a microscope

Explanation:

6 0
3 years ago
Read 2 more answers
Which of the following are true (choose all that apply)? Sound can travel through a vacuum. -Sound can travel through water. Lig
Lunna [17]

Answer:

option (A) - false

option (B) - true

option (C) - true

option (D) - true

option (E) - true

option (F) - true

Explanation:

The sound waves are mechanical waves that means they need a medium to travel.

The light waves are non mechanical waves it means they do not need a medium to travel.

Sound cannot travel trough vacuum.

Sound can travel through air and water.

Light can travel trough vacuum and in air and in water.

7 0
2 years ago
The spin-drier of a washing machine revolving at 900.RPM slows down uniformly to 300.RPM while making 60. revolutions. Find the
jeyben [28]
<h2>Answer:</h2>

<u>Acceleration is </u><u>-10.57 rad/s²  </u>

<u>Time is </u><u>6 seconds</u>

<h2>Explanation:</h2><h3>a) </h3>

u=900rpm= 94.248 rad/s  

v =300rpm= 31.416 rad/s  

s=60 revolutions= 377 rad  

v²= u²+ 2as  

31.416² = 94.248²+ 2 * a * 377  

a = v²-u² / 2s

a= -10.57 rad/s²  

<h3>b) </h3>

Using 1st equation of motion

v-u/a = t

Putting the values

t = (31.4 - 94.2)/-10.57

t = 6 seconds

3 0
3 years ago
Describe how you expect the waveform and the sound you hear changes when you hit the tuning fork harder.
myrzilka [38]

Answer:

In a tuning fork, two basic qualities of sound are considered, they are

1) The pitch of the waveform: This pitch depends on the frequency of the wave generated by hitting the tuning fork.

2) The loudness of the waveform: This loudness depends on the intensity of the wave generated by hitting the tuning fork.

Hitting the tuning fork harder will make it vibrate faster, increasing the number of vibrations per second. The number of vibration per second is proportional to the frequency, so hitting the tuning fork harder increase the frequency. From the explanation on the frequency above, we can say that by increasing the frequency the pitch of the tuning fork also increases.

Also, hitting the tuning fork harder also increases the intensity of the wave generated, since the fork now vibrates faster. This increases the loudness of the tuning fork.

6 0
3 years ago
A ball is dropped from rest from the top of a cliff that is 24 m high. From ground level, a second ball is thrown straight upwar
sesenic [268]

Answer:

6.0 m below the top of the cliff

Explanation:

We can find the velocity at which the ball dropped from the cliff reaches the ground by using the SUVAT equation

v^2-u^2 = 2gd

where

u = 0 (it starts from rest)

g = 9.8 m/s^2 (acceleration of gravity, we assume downward as positive direction)

h = 24 m is the distance covered

Solving for h,

v=\sqrt{2gh}=\sqrt{2(9.8)(24)}=21.7 m/s

So the ball thrown upward is launched with this initial velocity:

u = 21.7 m/s

From now on, we take instead upward as positive direction.

The vertical position of the ball dropped from the cliff at time t is

y_1 = h - \frac{1}{2}gt^2

While the vertical position of the ball thrown upward is

y_2 = ut - \frac{1}{2}gt^2

The two balls meet when

y_1 = y_2\\h-\frac{1}{2}gt^2 = ut - \frac{1}{2}gt^2 \\h = ut \rightarrow t = \frac{h}{u}=\frac{24}{21.7}=1.11 s

So the two balls meet after 1.11 s, when the position of the ball dropped from the cliff is

y_1 = h -\frac{1}{2}gt^2 = 24-\frac{1}{2}(9.8)(1.11)^2=18.0 m

So the distance below the top of the cliff is

d=24.0 - 18.0 = 6.0 m

4 0
3 years ago
Other questions:
  • Compared to the earth would the sun appear to move more quickly across Mercury’s sky or more slowly? Why?
    13·1 answer
  • A 500g object falls off a cliff and losers 100 J from its gravitational potential energy store. if the gravitational field stren
    12·1 answer
  • Sound waves have relatively long wavelengths. We can hear people around the corner before we can see them. Which wave behavior d
    9·1 answer
  • Lifting a box off the floor is an example of what type of force?
    5·2 answers
  • The density of atmosphere (measured in kilograms/meter3) on a certain planet is found to decrease as altitude increases (as meas
    6·1 answer
  • Observations of the Crab Nebula taken over several decades show that gas blobs that are now 100 arcseconds from the center of th
    10·1 answer
  • Help with these questions
    5·1 answer
  • State a Newtowns second law​
    15·1 answer
  • Let A^=6i^+4j^_2k^ and B= 2i^_2j^+3k^. find the sum and difference of A and B​
    8·1 answer
  • A trombone acts as if it were an
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!