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Andreyy89
3 years ago
14

Select the correct answer.

Physics
2 answers:
Art [367]3 years ago
8 0

The gravitational potential energy of the object is B) 84 Joules

Explanation:

The gravitational potential energy (GPE) of an object is the energy possessed by the object by virtue of its position in a gravitational field.

Near the Earth's surface, the GPE of an object is calculated as:

GPE=mgh

where:

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity

h is the heigth of the object relative the surface

For the object in this problem:

m = 5.24 kg

h = 1.63 m

So, its GPE is

GPE=(5.24)(9.8)(1.63)=84 J

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

marusya05 [52]3 years ago
4 0

Answer:

the answer to this question is option B. 84 joules

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As a substance is changing from a liquid to a gas, the distance
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As a substance is changing from a liquid to a gas, the distance between its molecules increases, and the temperature of the system remains the same.

Option A

<u>Explanation:</u>

The external energy required to change from one state to another is mostly considered as temperature. So on increase in temperature, the solid changes to liquid and the liquid changes to gases. But the temperature remains constant in the system after changing the phase.

This is because when the temperature is increased on a liquid system, the rise in temperature is utilized for breaking the bonds and thus the molecules will be distanced from each other. If we consider liquid - gas phase transition, the gas molecules are farther distanced compared to liquid molecules.

So the rise in temperature is utilized for breaking the bonds and also to provide the kinetic energy to the gas molecules as they are tend to move more freely compared to liquid. Thus, the distance between the molecules increases, and the temperature of the system remains the same on changing from liquid to gas.

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3 years ago
A fighter bomber is making a bombing run flying horizontally at 500 knots (256m/s) at an altitude of 100.0m.
Jobisdone [24]

Answer:

<em>(a) t = 4.52 sec</em>

<em>(b) X = 1,156.49 m</em>

Explanation:

<u>Horizontal Launching </u>

If an object is launched horizontally, its initial speed is zero in the y-coordinate and the horizontal component of the velocity v_o remains the same in time. The distance x is computed as .

\displaystyle x=v_o.t

(a)

The vertical component of the velocity v_y starts from zero and gradually starts to increase due to the acceleration of gravity as follows

v_y=gt

This means the vertical height is computed by

\displaystyle h=h_o-\frac{gt^2}{2}

Where h_o is the initial height. Our fighter bomber is 100 m high, so we can compute the time the bomb needs to reach the ground by solving the above equation for t knowing h=0

\displaystyle t=\sqrt{\frac{2h_o}{g}}

\displaystyle t=\sqrt{\frac{2(100)}{9.8}}=4.52\ sec

(b)

We now compute the horizontal distance knowing v_o=256\ m/s

\displaystyle x=(256).(4.52)

X=1,156.49\ m

4 0
2 years ago
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Answer:

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2 years ago
How much work is done if a force of 20 N moves an object a distance of 6 m?​
Nesterboy [21]

Explanation:

W=F×s

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W=120J

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2 years ago
Sam is recklessly driving 60 mph in a 30 mph speed zone when he suddenly sees the police. he steps on the brakes and slows to 30
barxatty [35]
For this problem, we use the derived equations for rectilinear motion at constant acceleration. The equations used for this problem are:

a = (v - v₀)/t
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v is the final velocity
v₀ is the initial velocity
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