Answer:
Option C is the correct answer.
Explanation:
Absolute pressure is sum of gauge pressure and atmospheric pressure.
That is
We have
Substituting
Option C is the correct answer.
Select the correct answer.
2 answers:
The gravitational potential energy of the object is B) 84 Joules
Explanation:
The gravitational potential energy (GPE) of an object is the energy possessed by the object by virtue of its position in a gravitational field.
Near the Earth's surface, the GPE of an object is calculated as:
where:
m is the mass of the object
is the acceleration of gravity
h is the heigth of the object relative the surface
For the object in this problem:
m = 5.24 kg
h = 1.63 m
So, its GPE is
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The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.
The given parameters;
- time of fall of the first ball, t = 1 s
- time of fall of the second ball, t = 3 s
The distance traveled by each ball is calculated using the second equation of motion as shown below.
The distance traveled by the first ball is calculated as follows;
The distance traveled by the second ball is calculated as follows;
Thus, the second ball traveled a greater distance because it spent more time in motion.
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Answer:
<em>The velocity of the carts after the event is 1 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum </u>
The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is
P=mv.
If we have a system of bodies, then the total momentum is the sum of the individual momentums:
If a collision occurs and the velocities change to v', the final momentum is:
Since the total momentum is conserved, then:
P = P'
In a system of two masses, the equation simplifies to:
If both masses stick together after the collision at a common speed v', then:
The common velocity after this situation is:
The m1=2 kg cart is moving to the right at v1=5 m/s. It collides with an m2= 8 kg cart at rest (v2=0). Knowing they stick together after the collision, the common speed is:
The velocity of the carts after the event is 1 m/s