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Pepsi [2]
3 years ago
14

How will a current change if the resistance of a circuit remains constant while the voltage across the circuit decreases to half

its original value?
1. The current will drop to half of its original value.
2. It is impossible to predict.
3. The current will triple.
4. The current will remain the same.
5. The current will double.
Physics
1 answer:
beks73 [17]3 years ago
4 0

Answer:

1. The current will drop to half of its original value.

Explanation:

The problem can be solved by using Ohm's law:

V=RI

where

V is the voltage across the circuit

R is the resistance of the circuit

I is the current

We can rewrite it as

I=\frac{V}{R}

In this problem, we have:

- the resistance of the circuit remains the same: R' = R

- the voltage is decreased to half of its original value: V'=\frac{V}{2}

So, the new current will be

I'=\frac{V'}{R'}=\frac{V/2}{R}=\frac{1}{2}\frac{V}{R}=\frac{I}{2}

so, the current will drop to half of its original value.

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My mass is 65 kg and on Earth this equals a weight of 640 N, but on the moon where gravity is 1.7 m/s² my
Helen [10]

Your weight on the moon given the data from the question is 110.5 N

<h3>Definition of mass and weight </h3>

Mass is simply defined as the quantity of matter present in an object. The mass of an object is constant irrespective of the location of the object.

Weight is simply defined as the gravitational pull on an object. The weight of an object varies from place to place due to gravity.

<h3>Relationship between mass and weight </h3>

Mass and weight are related according to the following equation

Weight (W) = mass (m) × Acceleration due to gravity (g)

<h3>How to determine the weight on the moon</h3>
  • Mass (m) = 65 Kg
  • Acceleration due to gravity on the moon (g) = 1.7 m/s²
  • Weight (W) =?

W = mg

W = 65 × 1.7

W = 110.5 N

Learn more about mass and weight:

brainly.com/question/14684564

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4 0
1 year ago
A stubborn, 100 kgkg mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope around
jolli1 [7]

Answer:

No, the farmer is not able to move the mule.

Explanation:

Mass =100 kg

Force=F=800 N

The coefficient between the mule and the ground=\mu_s=0.8

\mu_k=0.5

Static friction force,f=\mu N

Normal force=N=mg

Static friction force,f=\mu_s mg=0.8\times 100\times 9.8=784 N

Using g=9.8m/s^2

F<f

Static friction force is greater than applied force.

Therefore , the farmer is not able to move the mule.

4 0
3 years ago
When you walk across the ground and push on it with your feet...
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Answer:

The ground pushes back on your feet with equal force.

Explanation:

Newton's Laws of Motion

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timama [110]

Answer:

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Explanation:

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For a sample of mass 1.2 mg, the amount of uranium is:

1.2\, mg \cdot \frac{1}{250000}=4.8 \cdot 10^{-6}\,mg

7 0
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The answer is: Expressive vocabulary

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This would include all words in the child vocabulary, starting from the child's   written language, spoken language or even the child's manually signed words.

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