The butane is a kind of alkane. And there is only carbon and hydrogen and single bonds. The formula of butane is C4H10. There are four carbon atoms and ten hydrogen atoms present in one butane molecule.
Neutralization reaction means the reactants must be one acid and one alkali, and the product will be H2O and metal salt.
The only one satisfying this will be B
Answer:
The answer to your question is
4C₇H₁₇ + 45 O₂ ⇒ 28 CO₂ + 34H₂O
Explanation:
Write the equation
C₇H₁₇ + O₂ ⇒ CO₂ + H₂O
Process
1.- Check if the equation is balanced
Reactants Element Products
7 C 1
17 H 2
2 O 3
As the number of reactants and products is different, we conclude that the reaction is unbalanced.
2.- Write a coefficient "7" to CO₂ and a coefficient of 17/2 to H₂O
C₇H₁₇ + O₂ ⇒ 7CO₂ +
H₂O
Reactants Element Products
7 C 7
17 H 17
2 O 51/2
3.- Write a coefficient of 45/2 to the O₂, and multiply all the equation by 2.
4C₇H₁₇ + 45 O₂ ⇒ 28 CO₂ + 34H₂O
Reactants Element Products
28 C 28
68 H 68
90 O 90
The formula is easy:
Gram formula mass
----------------------------
Emprical Formula
So if we plug in our own numbers,
114.0
--------
57.116
We get an answer of 1.99, which rounds to 2.
Then, we distribute based off of our empirical formula.
2(C4H9) becomes C8H18.
Our molecular formula is C8H18.
Hope I could help!
Na + NaNO3 = Na2O + N2
4 Na + 2 NaNO3 = 6 Na2O + N2
6 Na on each side
2 N on each side
6 O on each side