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Nutka1998 [239]
3 years ago
6

Volcano help! *I GIVE THANKS!*

Chemistry
1 answer:
Pani-rosa [81]3 years ago
5 0
A volcanic <em>eruption</em> occurs when the <em>pressure </em> in a magma <em>chamber</em> becomes so great it is released like a valve. Magma is released through the volcano's <em>cone</em> in an eruption of <em>lava</em> rocks (bombs) and ash. A volcanic <em>cone</em> develops over centuries as flowing <em>lava</em> from the active volcano <em>cools </em>to form layers of rock. 
Hope this works,
Ahawk
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Mixture formation is a ________change.​
xxMikexx [17]
Chemical should be your answer.
6 0
3 years ago
If a buffer contains 1.05M B and 0.750M BH+ has the pH of 9.5. What would be the pH after 0.005mol of HCL is added to 0.5L of so
Leviafan [203]

Answer:

Final pH: 9.49.

Round to two decimal places as in the question: 9.5.

Explanation:

The conjugate of B is a cation that contains one more proton than B. The conjugate of B is an acid. As a result, B is a weak base.

What's the pKb of base B?

Consider the Henderson-Hasselbalch equation for buffers of a weak base and its conjugate acid ion.

\displaystyle \text{pOH} = \text{pK}_b + \log{\frac{[\text{Salt}]}{[\text{Base}]}}.

\text{pOH} = \text{pK}_w - \text{pH}.

\text{pK}_w = 14.

\text{pOH} = 14 - 9.5 = 4.5

\displaystyle \text{pK}_b = \text{pOH} -\log{\frac{[\text{Salt}]}{[\text{Base}]}}\\\phantom{\text{pK}_b} = 4.5 - \log{\frac{0.750}{1.05}} \\\phantom{\text{pK}_b} =4.64613.

What's the new salt-to-base ratio?

The 0.005 mol of HCl will convert 0.005 mol of base B to its conjugate acid ion BH⁺.

Initial:

  • n(\text{B}) = c\cdot V = 1.05 \times 0.5 = 0.525\;\text{mol};
  • n(\text{BH}^{+}) = c\cdot V = 0.750 \times 0.5 = 0.375\;\text{mol}.

After adding the HCl:

  • n(\text{B}) = 0.525 - 0.005 = 0.520\;\text{mol};
  • n(\text{BH}^{+}) = 0.375+ 0.005 = 0.380\;\text{mol}.

Assume that the volume is still 0.5 L:

  • \displaystyle [\text{B}] = \frac{n}{V} = \frac{0.520}{0.5} = 1.04\;\text{mol}\cdot\text{dm}^{-3}.
  • \displaystyle [\text{BH}^{+}] = \frac{n}{V} = \frac{0.380}{0.5} = 0.760\;\text{mol}\cdot\text{dm}^{-3}.

What's will be the pH of the solution?

Apply the Henderson-Hasselbalch equation again:

\displaystyle \text{pOH} = \text{pK}_b + \log{\frac{[\text{Salt}]}{[\text{Base}]}} = 4.64613 + \log{\frac{0.760}{1.04}} = 4.50991

\text{pH} = \text{pK}_w - \text{pOH}= 14 - 4.50991 = 9.49.

The final pH is slightly smaller than the initial pH. That's expected due to the hydrochloric acid. However, the change is small due to the nature of buffer solutions: adding a small amount of acid or base won't significantly impact the pH of the solution.

3 0
3 years ago
An organic acid is composed of carbon (45.45%), hydrogen (6.12%), and oxygen (48.44%). Its molar mass is 132.12 g/mol. Determine
Andreas93 [3]

Answer:

C4H8O4

Explanation:

To determine the molecular formula, first, let us obtain the empirical formula. This is illustrated below:

From the question given, we obtained the following information:

C = 45.45%

H = 6.12%

O = 48.44%

Divide the above by their molar mass

C = 45.45/12 = 3.7875

H = 6.12/1 = 6.12

O = 48.44/16 = 3.0275

Divide by the smallest

C = 3.7875/3.0275 = 1

H = 6.12/3.0275 = 2

O = 3.0275/3.0275 = 1

The empirical formula is CH2O

The molecular formula is given by [CH2O]n

[CH2O]n = 132.12

[12 + (2x1) + 16]n = 132.12

30n = 132.12

Divide both side by the coefficient of n i.e 30

n = 132.12/30 = 4

The molecular formula is [CH2O]n = [CH2O]4 = C4H8O4

7 0
3 years ago
Read 2 more answers
Scoring Scheme: 3-3-2-1 Use one of your experimentally determined values of k, the activation energy you determined, and the Arr
Lena [83]

Answer:

K = 2.7x10⁻⁵ at 25ºC

Explanation:

A way to write Arrhenius equation is:

ln K = - Ea/R × (1/T) + lnA

If you graph ln K as Y and 1/T as X (Absolute temperature in K), the equation you will obtain is:

Y = -13815X +35.817

R² = 0.9927

(Taking the last k point as 0.0386) (ln 0.0386), <em>0.1386 has no sense</em>)

Your slope is -13815

-13815K = - Ea/R

-13815K×8.314J/molK = 114858J/mol = Ea

And your intercept =

lnA = 35.817

A = 3.59x10¹⁵

Now, you want to know rate constant at 25ºC = 298.15K. Replacing in the equation (Where Y is ln (activation energy) and X is 1/T):

Y = -13815X +35.817

Y = -13815(1/298.15K) +35.817

Y = -10.5187

lnK = -10.5187

<h3>K = 2.7x10⁻⁵ at 25ºC</h3>

8 0
3 years ago
How does the atmosphere make conditions on earth suitable for living things
hram777 [196]
The atmosphere provides C02 for us, it protects us from the Sun's UV rays, it protects us from many objects in space that could crash into earth without it, and it holds the moisture in the air.
8 0
3 years ago
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