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3 years ago

Compare the density of gases in the thermosphere to the density at sea level.

Chemistry

1 answer:

Anestetic [448]3 years ago

8 0

Answer:

The atmosphere is 10 million times

Explanation:

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A scientist measures the standard enthalpy change for the following reaction to be 81.1 kJ :2CO2(g) + 5 H2(g)C2H2(g) + 4 H2O(g)B

posledela

<u>Answer:</u> The enthalpy of the formation of $CO_2(g)$ is coming out to be -410.8 kJ/mol.Z

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H^o$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]$

For the given chemical reaction:

$2CO_2(g)+5H_2(g)\rightarrow C_2H_2(g)+4H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(C_2H_2(g))})+(4\times \Delta H^o_f_{(H_2O(g))})]-[(2\times \Delta H^o_f_{(CO_2(g))})+(5\times \Delta H^o_f_{(H_2(g))})]$

We are given:

$\Delta H^o_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H^o_f_{(H_2(g))}=0kJ/mol\\\Delta H^o_f_{(C_2H_2(g))}=226.7kJ/mol\\\Delta H^o_{rxn}=81.1kJ$

Putting values in above equation, we get:

$81.1=[(1\times (226.7)})+(4\times (-241.8))]-[(2\times \Delta H^o_f_{(CO_2(g))})+(5\times (0))]\\\\\Delta H^o_f_{(CO_2(g))}=-410.8kJ/mol$

Hence, the enthalpy of the formation of $CO_2(g)$ is coming out to be -410.8 kJ/mol.

8 0

3 years ago

Heat is a form of energy transfer from a _____________________ _______________________ location to a_____________________ ______

Lesechka [4]

Answer:

hotter location to a colder location

4 0

3 years ago

Read 2 more answers

A physical change is a change (4 points) in the properties of matter that does not change the identity of the substance in the p

goblinko [34]

Yes a physical change can do that. A chemical change is like a burning candal

4 0

3 years ago

If 1.2 kilograms of rust forms on a bridge in 5 days, what should be the rate of reaction in grams per hour?

Dimas [21]

We have 1.2 kg of rust whithin 5 days.
the rate of reaction in grams per hour:

1.2 kg/5 day * 1000 g/kg * 1 day/24 hours = 10.0 grams/hour

hope this help

8 0

4 years ago

Which of the following metals is soluble in water with S2-?

Brut [27]

Strontium is soluble with s2-

6 0

3 years ago