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3 years ago

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Convertible bonds are examples of: a. Securities that have characteristics of both debt and equity b. Non-recurring items c. Ass

ets d. Treasury stock

1 answer:

iren2701 [21]3 years ago

5 0

Answer:

a. Securities that have characteristics of both debt and equity

Explanation:

A convertible bond is a debt security that can be converted into a certain number of shares and this can be done during specific times in the life of the bond. According to this, convertible bonds are examples of securities that have characteristics of both debt and equity as they are a type of debt that pays interest but can be turned into shares.

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A chemist fills a reaction vessel with 9.20 atm nitrogen monoxide (NO) gas, 9.15 atm chlorine (CI) gas, and 7.70 atm nitrosyl ch

ivanzaharov [21]

Answer:

The reactions free energy $\Delta G = -49.36 kJ$

Explanation:

From the question we are told that

The pressure of (NO) is $P_{NO} = 9.20 \ atm$

The pressure of (Cl) gas is $P_{Cl} = 9.15 \ atm$

The pressure of nitrosly chloride (NOCl) is $P_{(NOCl)} = 7.70 \ atm$

The reaction is

$2NO_{(g)} + Cl_2 (g)$ ⇆ $2 NOCl_{(g)}$

From the reaction we can mathematically evaluate the $\Delta G^o$ (Standard state free energy ) as

$\Delta G^o = 2 \Delta G^o _{NOCl} - \Delta G^o _{Cl_2} - 2 \Delta G^o _{NO}$

The Standard state free energy for NO is constant with a value

$\Delta G^o _{NO} = 86.55 kJ/mol$

The Standard state free energy for $Cl_2$ is constant with a value

$\Delta G^o _{Cl_2} = 0kJ/mol$

The Standard state free energy for $NOCl$ is constant with a value

$\Delta G^o _{NOCl} =66.1kJ/mol$

Now substituting this into the equation

$\Delta G^o = 2 * 66.1 - 0 - 2 * 87.6$

$= -43 kJ/mol$

The pressure constant is evaluated as

$Q = \frac{Pressure \ of \ product }{ Pressure \ of \ reactant }$

Substituting values

$Q = \frac{(7.7)^2 }{(9.2)^2 (9.15) } = \frac{59.29}{774.456}$

$= 0.0765$

The free energy for this reaction is evaluated as

$\Delta G = \Delta G^o + RT ln Q$

Where R is gas constant with a value of $R = 8.314 J / K \cdot mol$

T is temperature in K with a given value of $T = 25+273 = 298 K$

Substituting value

$\Delta G = -43 *10^{3} + 8.314 *298 * ln [0.0765]$

$= -43-6.36$

$\Delta G = -49.36 kJ$

4 0

3 years ago

and amounts of reactants: 2.01 g salicylic acid + 5.00 mL acetic anhydride (plus 5 drops of 85% phosphoric acid) a) If the densi

irakobra [83]

Answer:

see explanation below

Explanation:

Now. According to the context of this problem, I'm assuming you are doing the synthesis reaction of aspirin, which is a 1:1 ratio and the reaction is:

C7H6O3 + C4H6O3 ------> C9H8O4 + CH3COOH

Now that we know the general reaction, first, let's get the mass of acetic anhydride

m = d*V = 1.08 * 5 = 5.4 g

Now, with the molar mass of each reactants:

MM of SA = 138.12 g/mol

MM of AA = 102.09 g/mol

MM of aspyrin = 180.16 g/mol

Let's calculate now the moles:

moles of SA = 2.01 / 138.12 = 0.015 moles

moles of AA = 5.4 / 102.09 = 0.053 moles

As we can see in the reaction, 1 mole of SA reacts with 1 mole of AA but we have 0.015 of SA and 0.053 of AA, This means that the limiting reagent is the SA, therefore, it will be the first to be consumed in the reaction.

Now the theorical yield of Aspirin is:

m = 0.015 * 180.16 = 2.7024 g

The purpose of the phosphoric acid is to convert the anhydride acetic into an acid form, therefore, the Salycid acid (The OH) can act as nucleophile and react with the carbonile of the anydride. In this way, we can form the aspirin,

6 0

3 years ago

Explain how you would find the mass percent<br> of each element in water.

nydimaria [60]

Answer:

finding the mass percentage oven element in a compound might sound complicated, but the calculation is simple. For example, to determine the mass percentage of hydrogen in water H2O, divide the major mass of hydrogen by the total molar mass of water and then multiply the result by 100

3 0

3 years ago

After performing a dilution calculation, you determine you need 25.0 milliliters of an aqueous stock solution to make 100.0 mill

Strike441 [17]

To solve this we use the equation,

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

We prepare the solution by measuring 25 mL of the stock solution in a graduated cylinder or by using a pipette. Then, put the stock solution in a 100mL of volumetric flask. Dilute it by adding distilled water up to the 100mL mark in the flask. It should be noted that the lower meniscus of the solution should be the point where you observe the volume.

5 0

4 years ago

A) The lab tech called in sick today and you are called in to help prepare

jarptica [38.1K]

<h3>Answer:</h3>

318.405 g

<h3>Explanation:</h3>

We are given;

Volume of K₃PO₄ solution to be prepared as 750.0 mL or 0.75 L
Molarity of the solution to be prepared as 2.00 M

We are required to determine the mass of K₃PO₄ to be measured.

<h3>Step 1: Determine the number of moles of K₃PO₄</h3>

Molarity = Moles ÷ Volume

Rearranging the formula;

Number of moles = Molarity × Volume

Therefore;

Moles of K₃PO₄ = 2.00 M × 0.75 L

= 1.5 moles

<h3>Step 2: Determine the mass of K₃PO₄ to be measured</h3>

Mass = Number of moles × Molar mass

Molar mass of K₃PO₄ = 212.27 g/mol

Therefore;

Mass of K₃PO₄ = 1.5 moles × 212.27 g/mol

= 318.405 g

Therefore, the mass of K₃PO₄ that should be weighed is 318.405 g

7 0

3 years ago