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2 years ago

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Convert 35.0 m/s to cm/min

1 answer:

swat322 years ago

3 0

35 m/s = 210000 cm/min
35*600=210000

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Justin mixed two clear liquids together during an experiment and made the following observations:

svp [43]

Answer:

B. A chemical change occurred which caused the liquid's physical properties to change.

Explanation:

The reduction of the temperature of the system meant that the reaction absorbed heat energy from it. This shows that a chemical reaction was in progress. New products were formed, and this is proved by the change in the color to blue.

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2 years ago

Read 2 more answers

2 NO + O22 NO2 is second order in NO and first order in O2. Complete the rate law for this reaction in the box below. Use the fo

riadik2000 [5.3K]

Answer : The value of rate of reaction is $1.35\times 10^{-8}Ms^{-1}$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given chemical equation is:

$2NO+O_2\rightarrow 2NO_2$

Rate law expression for the reaction is:

$\text{Rate}=k[NO]^a[O_2]^b$

As per question,

a = order with respect to $NO$ = 2

b = order with respect to $O_2$ = 1

Thus, the rate law becomes:

$\text{Rate}=k[NO]^2[O_2]^1$

Now, calculating the value of rate of reaction by using the rate law expression.

Given :

k = rate constant = $9.87\times 10^3M^{-2}s^{-1}$

[NO] = concentration of NO = $7.86\times 10^{-3}M$

$[O_2]$ = concentration of $O_2$ = $2.21\times 10^{-3}M$

Now put all the given values in the above expression, we get:

$\text{Rate}=(9.87\times 10^3M^{-2}s^{-1})\times (7.86\times 10^{-3}M)^2\times (2.21\times 10^{-3}M)^1$

$\text{Rate}=1.35\times 10^{-8}Ms^{-1}$

Hence, the value of rate of reaction is $1.35\times 10^{-8}Ms^{-1}$

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2 years ago

A student determines that a 9.8 g mixture of MgCl₂ (s) and NaNO3(s) contains 0.050 mol of

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mass MgCl₂ = mol x MM MgCl₂ = 0.05 x 95.211 g/mol = 4.76 g

mass Cl in MgCl₂ :

= (2 x AM Cl)/MM MgCl₂ x mass MgCl₂

= (2 x 35.5 g/mol)/95.211 g/mol x 4.76

= 3.55 g

% mass Cl in the mixture :

= (mass Cl / mass mixture) x 100%

= 3.55 / 9.8 x 100%

= 36.22%

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1 year ago

Heating most solids sufficiently ________________ turning the solid into a liquid.

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An ice cube when you heat it it can to water and water is liquid of course

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118g of o2 gas is held at STP what is the volume of gas

shutvik [7]

Answer:

At STP one mole of any gas occupies a volume of 22.4 L: this is the molar volume.

Explanation:

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3 years ago