A gas has a volume of 46.0 L when the temperature is 400. K. When the temperature changes to 500. K, what is the new volume, if
1 answer:
Answer:
The correct answer is 57.5 L
Explanation:
According to the Charles's Law, as the temperature of a gas increases at constant pressure, its volume increases (the gas is expanded when it is heated). The mathematical expresion for two conditions (1 and 2) of a gas is the following:
Where V₁ and V₂ are the volumes of the gas in two different conditions (1 and 2); T₁ and T₂ are the temperatures in Kelvin of the gas in the two conditions 1 and 2.
In this case, V₁= 46.0 L and T₁= 400 K. Then, we heat the gas until it reaches T₂=500 K. In order to calculate the new volume (V₂), we introduce the data in the mathematical expression:
V₂= x T₂
V₂= (46.0 L/ 400 K) x 500 K
V₂= 57.5 L
We corroborate our answer is coherent because 57.5 L > 46.0 L as we know that the volume increases with the increase of temperature (from 400 K to 500 K).
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The algebraic expression would be:
<em>ppb [=] micrograms of compound/liter of solution</em>
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The respective procedure is in a attached file.
Answer:
Explanation:
25. Boyle's Law
The temperature and amount of gas are constant, so we can use Boyle’s Law.
Data:
Calculations:
26. Ideal Gas Law
We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.
pV = nRT
Data:
p = 101.3 kPa
V = 20 L
n = 5 mol
R = 8.314 kPa·L·K⁻¹mol⁻¹
Calculation:
101.3 × 20 = 5 × 8.314 × T
2026 = 41.57T