Question

A gas has a volume of 46.0 L when the temperature is 400. K. When the temperature changes to 500. K, what is the new volume, if there is no change in pressure or amount of gas

Answer 1

Answer:

The correct answer is 57.5 L

Explanation:

According to the Charles's Law, as the temperature of a gas increases at constant pressure, its volume increases (the gas is expanded when it is heated). The mathematical expresion for two conditions (1 and 2) of a gas is the following:

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

Where V₁ and V₂ are the volumes of the gas in two different conditions (1 and 2); T₁ and T₂ are the temperatures in Kelvin of the gas in the two conditions 1 and 2.

In this case, V₁= 46.0 L and T₁= 400 K. Then, we heat the gas until it reaches T₂=500 K. In order to calculate the new volume (V₂), we introduce the data in the mathematical expression:

V₂= $\frac{V_{1} }{T_{1} }$ x T₂

V₂= (46.0 L/ 400 K) x 500 K

V₂= 57.5 L

We corroborate our answer is coherent because 57.5 L > 46.0 L as we know that the volume increases with the increase of temperature (from 400 K to 500 K).