<span>To find the amount of heat energy required to raise a substance by a certain number of degrees, we simply multiply: (specific heat * change in temperature * mass)
Heat = 2.22 * 35 * 3 = 233.1 joules
Therefore, we would need 233.1 joules of heat to raise the temperature by 3 degrees Celsius.</span>
Answer:

Explanation:
Hello,
In this case, the undergoing chemical reaction is:

Thus, in terms of pressures, the rate becomes:

Thus, the rate of change for the partial pressure of ammonia turns out:
![r_{NH_3}=2*(-r_{N_2H_4})\\r_{NH_3}=2*[-(-70torr/h)]\\r_{NH_3}=140torr/h](https://tex.z-dn.net/?f=r_%7BNH_3%7D%3D2%2A%28-r_%7BN_2H_4%7D%29%5C%5Cr_%7BNH_3%7D%3D2%2A%5B-%28-70torr%2Fh%29%5D%5C%5Cr_%7BNH_3%7D%3D140torr%2Fh)
The rate of decrease of partial pressure of urea is taken negative as it is a reactant whereas ammonia a product which has 2 as its stoichiometric coefficient.
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Answer:
14 mol O₂
Explanation:
The reaction between CO and O₂ is the following:
CO + O₂ → CO₂
We balance the equation with a coefficient 2 in CO and CO₂ to obtain the same number of O atoms:
2CO + O₂ → 2CO₂
As we can see from the balanced equation, 1 mol of O₂ is required to react with 2 moles of CO. Thus, the conversion factor is 1 mol of O₂/2 mol CO. We multiply the moles of CO by the conversion factor to calculate the moles of O₂ that are required:
28 mol CO x 1 mol of O₂/2 mol CO = 14 mol O₂
Answer:
There are approximately 1.54 moles in a 275 g sample of
.
Explanation:
To find out number of moles, fistly we have to calculate molecular mass of
.
There are 2 atoms of Potassium 1 atom of Chromium and 3 atoms of oxygen in the given compound.
For molecular mass we have to add the value of mass of 2 atoms of Potassium with mass of 1 atom of Chromium and with mass of 3 atoms of oxygen.
Atomic mass of Potassium = 39
Atomic mass of Chromium = 52
Atomic mass of Oxygen = 16
Now,
Molecular mass of
= 
The molecular mass of a compound is the mass of compound in one mole.
To find out the number of moles, we have to divide given mass of compound by its molecular mass.


Hence the number of moles in 275 gm of
is 1.54.
Answer:
<u>B. Primary Consumer</u>
Explanation:
It is the top of the food chain in this example.