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azamat
2 years ago
10

The ground-state electron configuration for an element contains an unpaired 3s electron.

Chemistry
1 answer:
Lostsunrise [7]2 years ago
8 0

Answer:

The electron configuration of an element is the arrangement of its electrons in its atomic orbitals. By knowing the electron configuration of an element, we can predict and explain a great deal of its chemistry.

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36. What is the formula of pentaphosphorus decoxide?<br> A)P5010<br> B)PO 10<br> C)PO<br> D)P10 05
rosijanka [135]

Answer:

A)P5010

Explanation:

Penta- means 5 and deca/deco- means 10

3 0
3 years ago
Which pair are classified as chemical substances? Pick two.
maria [59]
Elements and compounds. This is because in solutions and mixtures the substances are not bonded to each other or pure, you can separate and purify substances in solutions and mixtures (via techniques such as distillation, filtering) but you cannot separate compounds as they are bonded together.
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When sodium chloride is dissolved in water, the resulting solution is classified as a?
Mice21 [21]
A homogeneous mixture is formed when it is dissolved in water
6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP
Mekhanik [1.2K]

The mass of magnesium, which has a density of 1.74 g/cm is 504.6 g.

<h3>What is mass?</h3>

Mass is the quantity of matter. Mass can be calculated by multiplying density by volume.

Magnesium is a chemical element with the atomic number 12. It is needed in the body in trace amounts. It can cause malnutrition in the body.

Mass = Density x volume

We know the density and the volume of magnesium.

Density = 1.74

Volume = 290

Density x volume

Putting the value in the equation

1.74 x 290 = 504.6 g

Thus, the mass of magnesium is 504.6 g.

To learn more about mass, refer to the below link:

brainly.com/question/22795877

#SPJ1

4 0
1 year ago
When you need to produce a variety of diluted solutions of a solute, you can dilute a series of stock solutions. A stock solutio
8090 [49]

Answer:

Volume of stock solution needed = 6.0299 mL

Explanation:

<u> </u>Dilution consists of lowering the amount of solute per unit volume of solution. It is achieved by adding more diluent to the same amount of solute.

This is deduced when thinking that both the dissolution at the beginning and at the end will have the same amount of moles.

<u>Data:</u>

M1 = 6.01 M stock solution concentration

M2 = 0.3624 M diluted solution concentration

V2 =100 mL diluted solution volume

V1 = ? stock solution volume

M1 * V1 = M2 * V2

V1=\frac{M2*V2}{M1} =\frac{0.3624M*100mL}{6.01M} =6.0299 mL

4 0
3 years ago
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