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irakobra [83]
3 years ago
9

How many electrons in an atom can have each of the following quantum number or sublevel designations?

Chemistry
1 answer:
lutik1710 [3]3 years ago
6 0

Answer: a:6 electrons, b:10electrons, c: 2electrons

Explanation:

1.Principle quantum number(n)

n is the number of shell, it is a positive integer. The maximum number of electrons in a shell is 2(n2)

2.Azimuthal quantum number(l)

l is the number of subshell in the principal shell

The name of subshell are s, p, d, f

The number of nodes in each subshell is

s is l=0, p is l=1, d is l=2, f is l=3.

Each shell can have 2 x l + 1 sublevels, and each sublevel can accommodate maximum of 2 electrons and have two electrons.

A. n=2, l=1 then 2 x 1 + 1= 3 subshell, 3*2= 6 electrons in the p subshell

b. 3d, d is l = 2 then 2 x 2 + 1 = 5 sublevels, 5*2=10 electrons in the d subshell

c. 4s, s is l=0 then 2 x 0 + 1 = 1 sublevel, 1*2=2 electrons in the s subshell.

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Which of the following polyatomic ions will form an ionic compound with a single sodium ion?
vaieri [72.5K]

Answer:

Option B, HCO3 1-

Explanation:

The valence of Sodium ion is +1 and the valence of HCO3 is -1. Thus, sodium ion has an extra electron to be donated to complete its outer shell  while HCO3 needs an electron to complete its outer shell

Hence Na will combine with HCO3 to form NaHCO3

Option B is correct

5 0
3 years ago
Pls help me with this
Zina [86]

Answer:

[I_2]=[Br]=0.31M

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:

I_2+Br_2\rightleftharpoons 2IBr

Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:

K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}

Thus, we solve for x as show below:

\sqrt{1.2x10^2} =\sqrt{\frac{(2x)^2}{(2.0-x)^2}} \\\\10.95=\frac{2x}{2.0-x}\\\\21.91-10.95x=2x\\\\21.91=12.95x\\\\x=\frac{21.91}{12.95} \\\\x=1.69M

Therefore, the concentrations of both bromine and iodine are:

[I_2]=[Br]=2.0M-1.69M=0.31M

Regards!

8 0
3 years ago
The reaction represented above goes essentially to completion. The reaction takes place in a rigid, insulated vessel that is ini
Leni [432]

Answer:

44. (C) The temperature must decrease because the reaction is endothermic

45. (D) 3Pi

46. (C) It must be positive since positive since ΔG° is positive and ΔH° is positive

47. (B) The sum of the bond enthalpies of the bonds of the reactant is less than the sum of the bond enthalpies of the bonds of the products

Explanation:

Here we have

CH₃OH(g) → CO(g) + 2H₂(g)   ΔH° +91 kJ/mol_{rxn}

44. Since the reaction is endothermic, absorbs heat, temperature must decrease because the reaction is endothermic

45. Since the number of moles in the reactant is 1 and the number of moles in the product is 3, we have;

Pressure, P is directly proportional to the number of moles

Therefore, where the pressure in the reactant is Pi pressure in the products will be 3Pi

46 Since the reaction takes place spontaneously at 600 K, therefore ΔG is negative and ΔH is positive hence ΔS must be positive

47. Since the reaction is an endothermic reaction, the sum of the bond enthalpies of the bonds of the reactant is less than the sum of the bond enthalpies of the bonds of the products.

5 0
3 years ago
What makes radioisotopes useful for dating objects answers?
Rus_ich [418]
If they have a long halflife, you can tell how much time has gone by since the element last has changed on earth.
7 0
3 years ago
A blacksmith making a tool heats 525 grams of steel to 1230C . After hammering the steel ,she places it into a bucket of water t
mash [69]

Answer:

Q = 18625.95 j

Explanation:

Given data:

Mass of steel = 525 g

Initial temperature = 123 °C

Final temperature = 50 °C

Heat release by steel = ?

Specific heat capacity of steel = 0.486 j/g. °C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = T2  - T1

ΔT  = 123°C - 50°C

ΔT  = 73°C

Q = m.c. ΔT

Q = 525 g.  0.486 j/g.°C . 73°C

Q = 18625.95 j

3 0
3 years ago
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