Yes. A mixture can be made up of just elements without the use of a compound, you can also just use compounds in a mixture without any elements
Answer:
I feel that "The Mesosaurus could not swim between the continents in the open ocean, so the fossils
show that the continents must have been together in the past." Is the best answer.
Explanation:
Because this is a true statement and even scientists belive this is true.
Answer:
The child with the trait is heterozygous.
Explanation:
It's a little difficult to be sure without wider context. But my interpretation of both the graphic and the wording, is that the circle represents a person who has the trait, but not necessarily someone who expresses the trait. The square, on the other hand, seems to represent a person who does not have the trait at all.
Based on that, the squares would be hom-zygous--they possess two copies of a dominant version of the characteristic. And the circles would be heteroxygous--they possess two different versions, one recessive and one dominant.
Unfortunately, this is actually a poorly constructed question, and if the circles are intended to represent an individual who <em>expresses </em>the recessive trait, then the answer would be that the child is hom-zygous. But based on the exact wording of the question, the correct interpretation of the graphic should be as I've explained above.
Answer:

Explanation:
To convert from mole to atoms, we must use Avogadro's Number: 6.022*10²³. This number tells us the particles (atoms, ions, molecules, etc.) in 1 mole of a substance. In this case, the particles are atoms of argon.
Let's create a ratio.

Multiply by the given number of atoms.

Flip the fraction so the atoms of argon will cancel.




The original measurement of atoms has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 8 in the thousandth place tells us to round the 9 to a 0, which also rounds the 9 in the tenths place to a 0, then the 4 to a 5.

There are 5.00 moles of argon.