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SpyIntel [72]
3 years ago
8

Torque can be calculated by multiplying the force (N) applied at 90∘ to the lever arm at a distance (m) from the pivot point (po

int of rotation), the compound SI unit for the torque is N⋅m. If the force (at 90∘ to the lever arm) applied is 15 N and it is applied at 2.0 m from the pivot point (point of rotation), what is the torque on the lever?
Chemistry
2 answers:
AveGali [126]3 years ago
8 0
<span>If a lever has a constant force applied at 90∘ to the lever arm at a fixed distance from the pivot point (point of rotation), the torque on the lever is given by  Torque = force (at 90∘ to lever arm) × distance to pivot point Force should be perpendicular to the lever arm
Therefore; you would do 15N X 2.0 m = 30 Nm or 30Joules</span>
tino4ka555 [31]3 years ago
6 0

The Torque on the liver from pivot (Point of Rotation) is 30.0 Nm. Which can be calculated by multiplying the Applied force and distance from the pivot.

Further Explanations:

Torque:

The turning effect of force when it is applied on an object is called torque.

Formula:

T = F.d sin (Theta)

Here F is the applied force on the object  and d is the distance from the pivot(Point of Rotation).

S.I Unit:

S.I means the units given by the international system.

The S.I unit if torque is “Nm”.

Which can also be get from the formula of torque simply the si unit of force is “N” and od distance is “m” so the whole unit of torque is “Nm”.

Calculation:

Data:

F= 15N, d= 2.0m theta = 90 degree

Solution:

Here we can apply the Formula of Torque as follows:

T = F.d sin (90)     here sin (90) = 1.

T = 15N x 2.0m x 1

T = 30Nm (J)

So in this way you can calculate the torque by this formula. By this simple formula you can calculate the torque of all questions. This is very easy to understand Hop you understand how we calculate the torque of any object if its force and distance is given form the pivot(Rotating Point )and its and is at 90 degree

Answer Details:

Subject: Chemistry

Level: High School

Key Words:

Torque:

Formula

S.I Unit

Calculation

For further Evaluation:

brainly.com/question/4771410

brainly.com/question/258149

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For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ
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The transformation of H_2PO_4- (aq) to HPO_4^2-(aq)is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

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The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

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