Answer: The solution will remain yellow.
Explanation:
The flashlight's beam will all be refracted towards a central axis. But, this is still dependent on the type of lens that is used for the said activity. The speed of light will vary depending whether the lens is a concave or a convex lens. The exit point of the light will always head towards the central axis.
Answer:
Q= mc∆T(ice) + mLF(ice) + mc∆T(water) + mLV(water) + mc∆T(steam)
m=250 g = 0.25 kg = ¼ kg c(ice)= 2100 J/kg.K c(water)= 4200 J/kg.K LF(ice)= 333.7 kJ/kg LV(water)= 2256 kJ/kg c(steam)= 2080 J/kg.K
Explanation:
Q= ¼ × 2100 × (0°-(-30°)) + ¼ × 333700 + ¼ × 4200 × (100°-0°) + ¼ × 2256000 + ¼ × 2080 × (145°-100°)
Q= 15750 + 83425 + 105000 + 564000 + 23400
Q= 791575 J
Answer:
F=ma where F = force in N, m = mass in g and a = acceleration in 
Answer : (b) The rate law expression for the reaction is:
![\text{Rate}=k[SO_2]^2[O_2]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BSO_2%5D%5E2%5BO_2%5D)
Explanation :
Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
The general reaction is:

The general rate law expression for the reaction is:
![\text{Rate}=k[A]^a[B]^b](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BA%5D%5Ea%5BB%5D%5Eb)
where,
a = order with respect to A
b = order with respect to B
R = rate law
k = rate constant
and
= concentration of A and B reactant
Now we have to determine the rate law for the given reaction.
The balanced equations will be:

In this reaction,
and
are the reactants.
The rate law expression for the reaction is:
![\text{Rate}=k[SO_2]^2[O_2]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BSO_2%5D%5E2%5BO_2%5D%5E1)
or,
![\text{Rate}=k[SO_2]^2[O_2]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BSO_2%5D%5E2%5BO_2%5D)