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zzz [600]
3 years ago
9

Round 780,820 to the nearest ten thousand?

Mathematics
2 answers:
alekssr [168]3 years ago
7 0

780,000 is 780,820 rounded to the nearest ten thousand

Damm [24]3 years ago
4 0
780,000 is the answer to this question.
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Someone help me please
Jet001 [13]
The area of a square is the square of the sides, and in this case, equals 14*16=224 mm^2
So length of each side
= sqrt(224) =  14. 97 or 15 mm to the nearest integer.
5 0
3 years ago
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Work out the lengths of sides a and b.<br> Give your answers to 1 decimal place.
torisob [31]

Step-by-step explanation:

{a}^{2}  =  {8}^{2}  +  {5}^{2}  \\  {a }^{2}  = 64 + 25 \\  {a}^{2}  = 89 \\ a =  \sqrt{89}  = 9.4 \: cm

{17}^{2}  =  {12}^{2}  +  {b}^{2}  \\  {b}^{2}  =  {17}^{2}  -  {12}^{2}  \\  {b}^{2}  = 289 - 144 \\  {b}^{2}  = 145 \\ b = 12 \: cm

3 0
3 years ago
How many ways can 4 candy bars be chosen from a store that sells 30 candy bars (combination)
Morgarella [4.7K]

Answer:

Using the combination formula:

Number of combination of r object chosen from the total object i.e n is given by:

\frac{n!}{r! \cdot (n-r)!}

As per the statement:

4 candy bars be chosen from a store that sells 30 candy bars

Number of candy bars chosen from a store that sells 30 candy bars(r)= 4

and

Total candy bars(n) = 30

then substitute in the given formula we have;

\frac{30!}{4! \cdot (30-4)!}

⇒\frac{30!}{4! \cdot (26)!}

⇒\frac{30 \cdot 29 \cdot 28 \cdot 27 \cdot 26!}{1 \cdot 2 \cdot 3 \cdot 4 \cdot (26)!}

Simplify:

⇒\frac{657720}{24} = 27,405

therefore, 27,405  ways can 4 candy bars be chosen from a store that sells 30 candy bars

3 0
3 years ago
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One more thanfour times a number is thirteen what is the number
brilliants [131]

Answer:

3

Step-by-step explanation:

subtract 1 from 13 divide the number by 4

7 0
3 years ago
HELP AGAIN :))) PLEASE HELP
Zielflug [23.3K]

Answer:

55

Step-by-step explanation:

This is 55 because you need to make a sum of 180 when making a line and 125+55=180

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3 years ago
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