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3 years ago

The Lewis structure for a chlorate ion, ClO3-, should show single bond(s), double bond(s), and lone pair(s).

Chemistry

2 answers:

Yuliya22 [10]3 years ago

7 0

<u>Answer:</u> A molecule of $ClO_3^-$ has 1 single bond, 2 double bonds and 8 lone pairs.

<u>Explanation:</u>

Lewis-dot structure is defined as the structure which represents the number of valence electrons around the atoms. The electrons are represented as dots.

This structure helps in the determination of bonding electrons and non-bonding electrons.

For the given compound $ClO_3^-$

As we know that chlorine has '7' valence electrons and oxygen has '6' valence electron. The negative charge gets add up in the total number of valence electrons.

Total number of valence electrons in $ClO_3^-$ = 7 + 3(6) + 1 = 26

In $ClO_3^-$ , two electrons of 2 oxygen atoms combine with 2 electrons of chlorine and 1 electron of one oxygen atom combines with 1 electron of chlorine atom.

A lone pair remains on the central atom which is chlorine.

Hence, a molecule of $ClO_3^-$ has 1 single bond, 2 double bonds and 8 lone pairs.

eduard3 years ago

3 0

1 single bond, 2 double bond 2 lone pairs

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3 years ago

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An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure and temperature were 94.0mL,

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Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.85 atm

$P_2$ = final pressure of gas = 456 mm Hg = 0.60 atm (760mmHg=1atm)

$V_1$ = initial volume of gas = ?

$V_2$ = final volume of gas = 94.0 ml

$T_1$ = initial temperature of gas = $66^oC=273+66=339K$

$T_2$ = final temperature of gas = $113^oF=318K$ $(32^0F=273K)$

Now put all the given values in the above equation, we get:

$\frac{0.85\times V_1}{339}=\frac{0.60\times 94.0}{318}$

$V_1=70.7ml=0.0707L$ (1L=1000ml)

Thus the original volume in liters was 0.0707L

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2 years ago

1. A 50 gram sample of a radioisotope decays to 12.5 grams in 14.4 seconds. What is

stiv31 [10]

Answer:

Half life = 7.2 seconds

Explanation:

$from \: decay \: equation \\ 2.303 log( \frac{n.}{nt} ) = kt \\ 2.303 log( \frac{50}{12.5} ) = k \times 14.4 \\ k = \frac{2.303 log( \frac{50}{12.5} )}{14.4} \\ k = 0.096288 {s}^{ - 1} \\ since \: half \: life = \frac{ ln(2) }{k} \\ half \: life = \frac{ ln(2) }{0.096288} \\ half \: life = 7.2 \: seconds$

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2 years ago

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The Lewis structure for a chlorate ion, ClO3-, should show ____ single bond(s), ____ double bond(s), and ____ lone pair(s).

The Lewis structure for a chlorate ion, ClO3-, should show single bond(s), double bond(s), and lone pair(s).