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2 years ago

Explain why it is dangerous to burn a carbon-based fuel, such as propane or methane, in a closed room or building.

1 answer:

6 0

Setting a fire too or burning substances such as propane or methane in a closed room/building can very easily cause an open flame or fire to the area because they are flammable substances

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How many post does it take to support a fence 200 ft long if a post is every 20 feet?

Art [367]

10 because you divide 200 by 20

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2 years ago

Speed is defined as the distance an object travels per unit of time. Which TYPE of speed is observed when you look at the speedo

Eduardwww [97]

B.) Instantaneous speed because the speedometer shows how fast you are going at that giving time .

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2 years ago

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In part 2 of the experiment, you will be analyzing a sample of household bleach. A 0.0854 g sample of household bleach is comple

marysya [2.9K]

Answer:

The correct answer is option d.

Explanation:

$NaClO(aq)+2KI(s)+H_2O(l)\rightarrow NaCl(aq)+I_2(aq)+2KOH(aq)$ ..[1]

$I_2(aq)+2Na_2S_2O_3(aq)\rightarrow 2NaI(aq)+Na_2S_4O_6(aq)$ ..[2]

moles of sodium thiosulfate solution = n

Molarity of the sodium thiosulfate solution = 0.150 M

Volume of sodium thiosulfate solution used = 0.890 mL = 0.00089 L

$n=Molarity\times Volume (L)$

$n=0.150 M\times 0.00089 L=0.0001335 mol$

According to reaction [2], 2 moles of sodium thiosulfate reacts with 1 mol $I_2$ .

Then , 0.0001335 mol of sodium thiosulfate will reacts with:

$\frac{1}{2}\times 0.0001335 mol=0.00006675 mol$ of $I_2$

Moles of $I_2$ = 0.00006675 mol

According to reaction [1], 1 mol of $I_2$ is obatnied from 1 mol of NaClO.

Then 0.00006675 mol of $I_2$ will be obtained from:

$\frac{1}{1}\times 0.00006675 mol=0.00006675 mol$

Mass of 0.00006675 mol of NaClO=

0.00006675 mol × 74.44 g/mol = 0.00496887 g

Mass of sample = 0.0854 g

Percentage of NaClO in sample:

$\frac{0.00496887 g}{0.0854 g}\times 100=5.82\%$

4 0

3 years ago

Calculate the amount of heat energy in KJ required to convert 45.0 g of ice at -15.5'C to steam at 124.0°C. (Cwater 118 Jig'c, G

dangina [55]

Answer : The enthalpy change or heat required is, 139.28775 KJ

Solution :

The conversions involved in this process are :

$(1):H_2O(s)(-15.5^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(4):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)\\\\(5):H_2O(g)(100^oC)\rightarrow H_2O(g)(124^oC)$

Now we have to calculate the enthalpy change.

$\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]$

where,

$\Delta H$ = enthalpy change or heat required = ?

m = mass of water = 45 g

$c_{p,s}$ = specific heat of solid water = $2.09J/g^oC$

$c_{p,l}$ = specific heat of liquid water = $4.18J/g^oC$

$c_{p,g}$ = specific heat of liquid water = $1.84J/g^oC$

n = number of moles of water = $\frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{45g}{18g/mole}=2.5mole$

$\Delta H_{fusion}$ = enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

$\Delta H_{vap}$ = enthalpy change for vaporization = 40.67 KJ/mole = 40670 J/mole

Now put all the given values in the above expression, we get

$\Delta H=[45g\times 4.18J/gK\times (0-(-15.5))^oC]+2.5mole\times 6010J/mole+[45g\times 2.09J/gK\times (100-0)^oC]+2.5mole\times 40670J/mole+[45g\times 1.84J/gK\times (124-100)^oC]$

$\Delta H=139287.75J=139.28775KJ$ (1 KJ = 1000 J)

Therefore, the enthalpy change is, 139.28775 KJ

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2 years ago

What is the net ionic equation for the reaction of solid iron with aqueous copper sulfate? (Hint: First use the activity series

ASHA 777 [7]

For the answer to the question above,
The re<span>action of solid iron with aqueous copper sulfate is an example of a single displacement type of reaction which exchanges only the cations of the element and the compound. In this case, the equation is

Fe (s) + CuSO4 (aq) = FeSO4 + Cu (s) </span>

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2 years ago

Read 2 more answers