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vova2212 [387]
4 years ago
10

The elements in any blank in periodic table have similar physical and chemical properties

Chemistry
1 answer:
Yakvenalex [24]4 years ago
8 0
Elements in the same group have similar properties
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V2O5 + Ca = V + CaO balance the eqaution
andreyandreev [35.5K]

Answer: The balanced equation is V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO.

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, V_{2}O_{5} + Ca \rightarrow V + CaO

Here, number of atoms on reactant side are as follows.

  • V = 2
  • O = 5
  • Ca = 1

The number of atoms on product side are as follows.

  • V = 1
  • O = 1
  • Ca = 1

In order to balance this equation, multiply Ca by 5 on reactant side. Multiply V by 2 and CaO by 5 on product side. Therefore, the equation can be rewritten as follows.

V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO

Now here, number of atoms on reactant side are as follows.

  • V = 2
  • O = 5
  • Ca = 5

The number of atoms on product side are as follows.

  • V = 2
  • O = 5
  • Ca = 5

Since, there are same number of atoms on both reactant and product side. So, the equation is now balanced.

Thus, we can conclude that the balanced equation is V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO.

5 0
3 years ago
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stepladder [879]

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C. Light slows down as it goes through more dense materials.

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Suppose that 0.25 mole of gas C was added to the mixture without changing the total pressure of the mixture. How does the additi
Yanka [14]

Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.

On addition of 0.25 moles of C gas, the mole fraction of gas A will be  \frac{moles of gas A}{moles of gas A + 0.25}.

The partial pressure of gas A can be written as P_{A} = x_{A}×P (where x_{A} is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.

The mole fraction of gas A in a mixture of gas A and C is = \frac{moles of gas A}{moles of gas A + moles of gas C} and \frac{moles of gas C}{moles of gas A + moles of gas C} respectively.

Thus on addition of 0.25 moles of C gas, the mole fraction of gas A will be  \frac{moles of gas A}{moles of gas A + 0.25}.

Which is different from the initial state.

4 0
3 years ago
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Milk (pH 6.7)
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Ammonia is the most basic and has the highest OH- concentration since it has the highest pH.
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Balance Na2CrO4 + AlPO4
Sonbull [250]

Answer:

2Na3PO4 + Al2(CrO4)3

Explanation:

these are the products

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