The elements in any blank in periodic table have similar physical and chemical properties

Chemistry

1 answer:

Yakvenalex [24]4 years ago

8 0

Elements in the same group have similar properties

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V2O5 + Ca = V + CaO balance the eqaution

andreyandreev [35.5K]

Answer: The balanced equation is $V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO$ .

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, $V_{2}O_{5} + Ca \rightarrow V + CaO$

Here, number of atoms on reactant side are as follows.

V = 2
O = 5
Ca = 1

The number of atoms on product side are as follows.

V = 1
O = 1
Ca = 1

In order to balance this equation, multiply Ca by 5 on reactant side. Multiply V by 2 and CaO by 5 on product side. Therefore, the equation can be rewritten as follows.

$V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO$

Now here, number of atoms on reactant side are as follows.

V = 2
O = 5
Ca = 5

The number of atoms on product side are as follows.

V = 2
O = 5
Ca = 5

Since, there are same number of atoms on both reactant and product side. So, the equation is now balanced.

Thus, we can conclude that the balanced equation is $V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO$ .

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3 years ago

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stepladder [879]

Answer:

C. Light slows down as it goes through more dense materials.

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3 years ago

Suppose that 0.25 mole of gas C was added to the mixture without changing the total pressure of the mixture. How does the additi

Yanka [14]

Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.

On addition of 0.25 moles of C gas, the mole fraction of gas A will be $\frac{moles of gas A}{moles of gas A + 0.25}$ .

The partial pressure of gas A can be written as $P_{A}$ = $x_{A}$ ×P (where $x_{A}$ is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.

The mole fraction of gas A in a mixture of gas A and C is = $\frac{moles of gas A}{moles of gas A + moles of gas C}$ and $\frac{moles of gas C}{moles of gas A + moles of gas C}$ respectively.