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Vitek1552 [10]
2 years ago
15

Please help ASAP. No one could not help me with this question.

Chemistry
1 answer:
Tanya [424]2 years ago
3 0

Answer:

sorry

Explanation:

I don't know the answer this is really confusing but I am really sorry you have to do this.

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The solution you identified in question (1) acts as a buffer due to reactions that occur within the solution when an acid or a b
weeeeeb [17]

Answer:

The answer is "\bold{CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)}"

Explanation:

When HCI is added in the chemical equation it reacts with sodium acetate so, it will give the following chemical equation:

CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\

 In this, the CH_3COOH is a weak acid so, it not completely dissociated.

CH_3COONa \ (aq) \ \ and \ NaCl were strong electrolytes they are completely dissociated.

The HCl is a strong acid so, it is completely dissociated So, the net ionic equation is:

CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)

8 0
2 years ago
Convert these temperatures to Celsius:<br><br> a. 303 K<br><br> d. 45 K
andre [41]

303K − 273.15 = 29.85°C

45K − 273.15 = -228.1°C

8 0
2 years ago
The reaction below shows how silver chloride can be synthesized.
Vesna [10]
AgNO_{3} _{(aq)}  +  NaCl_{(aq)}  ----\ \textgreater \   NaNO_{3} _{(aq)}   +  AgCl _{(aq)}
mole ration of AgCl _{(aq)}  :  AgNO_{3} _{(aq)} =  1 : 1

∴ if moles of  AgNO_{3} _{(aq)} =  15.0 mol
then   "      "     AgCl _{(aq)}  =  15.0 mol

∴  the Option  2 is the answer.

5 0
3 years ago
Read 2 more answers
For a phase change, H0 = 2 kJ/mol and A S0 = 0.017 kJ/(K•mol). What are
34kurt

Answer:

ΔG = -6.5kJ/mol at 500K

Explanation:

We can find ΔG of a reaction using ΔH, ΔS and absolute temperature with the equation:

ΔG = ΔH - TΔS

Computing the values in the problem:

ΔG = ?

ΔH = 2kJ/mol

T = 500K

And ΔS = 0.017kJ/(K•mol)

Replacing:

ΔG = 2kJ/mol - 500K*0.017kJ/(K•mol)

ΔG = 2kJ/mol - 8.5kJ/mol

<h3>ΔG = -6.5kJ/mol at 500K</h3>

8 0
3 years ago
What is the valence of Fluorine
gayaneshka [121]
7 valance electrons and a atomic number of 9
7 0
3 years ago
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