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krok68 [10]
3 years ago
9

Billions of pounds of urea are produced annually for use as a fertilizer. Balance the skeletal equation for the synthesis of ure

a. Express your answer as a chemical equation. Identify all of the phases in your answer.
NH3(g)+CO2(g)==>CO(NH2)2(s)+H20(l)
Chemistry
1 answer:
klio [65]3 years ago
5 0
2NH₃(g) + CO₂(g) → CO(NH₂)₂(s) + H₂O(l)
is the balanced equation for the synthesis of urea.
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6. If 0.500 mol NaN3 react, what mass in grams of nitrogen will result?
lions [1.4K]

Answer:

21 g of N₂ are produced by the decomposition

Explanation:

The reaction is: 2 NaN3 → 2 Na + 3 N2

2 moles of sodium nitride decompose in order to produce 2 moles of Na and 3 moles of nitrogen gas.

According to stoichiometry, ratio is 2:3. Therefore we say,

2 moles of nitride can produce 3 moles of N₂

Then, 0.5 moles of NaN₃ will produce (0.5 . 3) / 2 = 0.75 moles of N₂

We convert the moles to mass, to find the answer

0.75 mol . 28 g / 1 mol = 21 g

7 0
3 years ago
Cutting, melting, bending, or crushing are examples of what kind of change?
Ksivusya [100]

Answer:

those are all physical changes and most physical changes can be undone like crushing a pice of metal you can flatten it back out you anwser is physical change

Explanation:

8 0
3 years ago
Read 2 more answers
A chemical reaction produced 177.3 grams of chlorine has (Cl²). What was the volume of the gas?
vichka [17]
Since there is so little information given, I will assume that we are at STP and i can use the conversion factor at STP--->> 22.4 Liters= 1 mol of gas

before we use this conversion, we need to convert the grams to moles using the molar mass of the molecule.

molar mass of Cl₂= 35.5 x 2= 71.0 g/ mol

177.3 g (1 mol/ 71.0 g)= 2.50 mol Cl₂

then we use the conversion to get the volume

2.50 mol Cl₂ (22.4 Liters/ 1 mol)= 55.9 Liters
3 0
4 years ago
Help!
babunello [35]
D.mno4- is reuced it loses h atom

7 0
3 years ago
Which statement is true about this equation?
lara [203]
The appropriate response is the fourth one. The announcement is valid about this condition beneath is in spite of the fact that it is unequal, it can be adjusted by specifically utilizing observer particles.

I hope the answer will help you. 

3 0
3 years ago
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