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krok68 [10]
3 years ago
9

Billions of pounds of urea are produced annually for use as a fertilizer. Balance the skeletal equation for the synthesis of ure

a. Express your answer as a chemical equation. Identify all of the phases in your answer.
NH3(g)+CO2(g)==>CO(NH2)2(s)+H20(l)
Chemistry
1 answer:
klio [65]3 years ago
5 0
2NH₃(g) + CO₂(g) → CO(NH₂)₂(s) + H₂O(l)
is the balanced equation for the synthesis of urea.
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How many grams of NaCl do you need to prepare 200 ml of a 5M solution? The molecular weight of NaCl is 58.4 g/mol. Smol 0.2L-1mo
Butoxors [25]

Answer:

The answer to your question is: 58.4 g of NaCl

Explanation:

Data

Volume = 200 ml = 0.2 l

Concentration = 5M

MW = 58.4 g

mass NaCl = ?

Formula

             Molarity = (# of moles ) / volume

             # of moles = Molarity x volume

             # of moles = 5 x 0.2

             # of moles = 1

              58.4 g ---------------------- 1 mol

              x          ---------------------  1 mol

              x = (1 x 58.4) / 1

             x = 58.4 g of NaCl

4 0
3 years ago
In forming a chelate with a metal ion, a mixture of free EDTA (abbreviated Y 4 − Y4− ) and metal chelate (abbreviated MY n − 4 M
Lyrx [107]

Answer:

There will 3.95 grams of Na2 and H2O that should be added to form a concentric required solution.

5 0
3 years ago
Classify the following reaction.
Klio2033 [76]

Answer:

Explanation:

combustion  reacts with oxygen

7 0
3 years ago
Nitric acid is a strong acid, sodium hydroxide is a strong base, and sodium nitrate is a soluble salt. Which of the following is
Evgesh-ka [11]
Can’t help with this but good luck
4 0
3 years ago
At a festival, spherical balloons with a radius of 280. Cm are to be inflated with hot air and released. The air at the festival
evablogger [386]

Answer:

8608.18 balloons

Explanation:

Hello! Let's solve this!

Data needed:

Enthalpy of propane formation: 103.85kJ / mol

Specific heat capacity of air: 1.009J · g ° C

Density of air at 100 ° C: 0.946kg / m3

Density of propane at 100 ° C: 1.440kg / m3

First we will calculate the propane heat (C3H8)

3000g * (1mol / 44g) * (103.85kJ / mol) * (1000J / 1kJ) = 7.08068 * 10 ^ 6 J

Then we can calculate the mass of the air with the heat formula

Q = mc delta T

m = Q / c delta T = (7.08068 * 10 ^ 6 J) / (1.009J / kg ° C * (100-25) ° C) =

m = 93566.96kg

We now calculate the volume of a balloon.

V = 4/3 * pi * r ^ 3 = 4/3 * 3.14 * 1.4m ^ 3 = 11.49m ^ 3

Now we calculate the mass of the balloon

mg = 0.946kg / m3 * 11.49m ^ 3 = 10.87kg

The amount of balloons is

93566.96kg / 10.87kg = 8608.18 balloons

5 0
3 years ago
Read 2 more answers
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