NH4 itself is called ammonium ion with positive charge of 1+. hence the oxidation state will be +1
OH itself is called hydroxide ion with negative charge of 1-. hence the oxidation state will be -1
there's actually no such compound as stated in your chemical formula. although it's simply called ammonium hydroxide by looking at the chemical formula, in fact the compound should rightly be called as aqueous ammonia with chemical formula of NH3 (aq). this is because the ammonia molecule will ionise due to the presence of water molecule to be protonated, hence forming ammonium ion and hydroxide ion in the solution.
Answer:
H₂ is excess reactant and O₂ the limiting reactant
Explanation:
Based on the chemical reaction:
2H₂(g) + O₂(g) → 2H₂O
<em>2 moles of H₂ react per mole of O₂</em>
<em />
To find limiting reactant we need to convert the mass of each reactant to moles:
<em>Moles H₂ -Molar mass: 2.016g/mol-:</em>
10g H₂ * (1mol / 2.016g) = 4.96 moles
<em>Moles O₂ -Molar mass: 32g/mol-:</em>
22g O₂ * (1mol / 32g) = 0.69 moles
For a complete reaction of 0.69 moles of O₂ are needed:
0.69mol O₂ * (2mol H₂ / 1mol O₂) = 1.38 moles of H₂
As there are 4.96 moles,
<h3>H₂ is excess reactant and O₂ the limiting reactant</h3>
Answer:
Chlorine has 17 total electrons with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5.
What are the first two quantum numbers for the six electrons in the 2p subshell?
Explanation:
The principal quantum number represents the shell number in which the electron is present.
It is represented with "n".
The next quantum number is the azimuthal quantum number.
It represents the shape of the orbital.
It has values from 0 to (n-1).
Its value depends on the principal quantum number.
Chlorine has 17 total electrons with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5.
For the six elecetrons in 2p subshell:
The first two quantum number values are the same and their values are:
n=2 , l=1.
Ooh Chemistry sucks. Try looking up parts of the question.
