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MA_775_DIABLO [31]
3 years ago
6

Help please? ASAP!!!!

Mathematics
1 answer:
Luda [366]3 years ago
4 0
Ok, your answer is 16x+7y/18x .-.
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Which of the following represents<br> this statement? |3x – 41 &lt; 2
agasfer [191]
<h2>Answer:</h2><h2>D is the correct answer </h2><h2></h2><h2>Hope this helps!!</h2>

3 0
3 years ago
Nakita recorded a video of homecoming highlights of the senior class and now everybody wants a copy. She promised to have 25 rea
alexira [117]
I would take  because it would take nakita 1 hour to do 2 and a half herself and it would take abby 1 2/3 to do it herself
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=1%2F2x%5E3%20%2B%20x%20-7%20%3D%20-3%5Csqrt%7Bx%7D%20%20-1" id="TexFormula1" title="1/2x^3 + x
Margaret [11]

Answer:

  none of the above

Step-by-step explanation:

The problem as written cannot have any of the solutions offered.

For any of those choices, the right side expression will be irrational. The left side expression will be rational for any rational value of x, so cannot be equal to the right-side expression.

The solution is an irrational number near ...

  x ≈ 1.33682898582

5 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!
NemiM [27]

Answer:

p<7

Step-by-step explanation:

$5 per pound

7 pounds equals $35

$5p<$35

p<35/5

p<7

7 0
3 years ago
A telemarketer is successful at getting people to donate money for her organization in 55% of all calls she makes. She must get
Tems11 [23]
An interesting twist to a binomial distribution problem.

Given:
p=55%=0.55 for probability of success in solicitation
x=4=number of successful solicitations
n=number of calls to be made
P(x,n,p)>=89.9%=0.899  (from context, it is >= and not =, which is almost impossible)

From context of question, all calls are assumed independent, with constant probability of success, so binomial distribution is applicable.

The number of successes, x, is then given by
P(x)=C(n,x)p^x(1-p)^{n-x}where
p=probability of success
n=number of trials
x=number of successesC(n,x)=\frac{n!}{x!(n-x)!}

Here we need n such that
P(x,n,p)>=0.899
given
x>=4, p=0.55, which means we need to find

Method 1: if a cumulative binomial distribution table is available, we can look up n=9,10,11 and find
P(x>=4,9,0.55)=0.834
P(x>=4,10,0.55)=0.898
P(x>=4,11,0.55)=0.939
So she must make (at least) 11 calls to make sure the probability of meeting her quota is 89.9% or more.

Method 2: using technology.
Similar to method 1, we can look up the probabilities directly, for n=9,10,11
P(x>=4,9,0.55)=0.834178
P(x>=4,10,0.55)=0.8980051
P(x>=4,11,0.55)=0.9390368

Method 3: using simple calculator
Here we need to calculate the probabilities for each value of n=10,11 and sum the probabilities of FAILURE S=P(0,n,0.55)+P(1,n,0.55)+P(2,n,0.55)+P(3,n,0.55)
so that the probability of success is 1-S.
For n=10,
P(0,10,0.55)=0.000341
P(1,10,0.55)=0.004162
P(2,10,0.55)=0.022890
P(3,10,0.55)=0.074603
So that
S=0.000341+0.004162+0.022890+0.074603
=0.101995
and Probability of getting 4 successes (or more) 
=1-S
=0.898005, missing target by 0.1%

So she will have to make 11 phone calls, bring up the probability to 93.9%.  The work is similar to that of n=10.
8 0
3 years ago
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