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3 years ago

I really hoped somebody helps me

Mathematics

2 answers:

slavikrds [6]3 years ago

8 0

There age this year will be 90

mamaluj [8]3 years ago

3 0

Answer: Their combined age will be 90.
2x+x=54 will allow you to find their ages. Solve for x ( this is Timothy's age) and you get 18. Times 2 is 36 for Paul's age. Finally, Timothy will be 36 in 18 years and in 18 years Paul will be 54. Add their ages together and you get 90.

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If x represents the amount Rita earns each week, which expression represents the amount she earns in a year?

Sphinxa [80]

There are 52 weeks in a year, so 52x represents how much she earns in a year.

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3 years ago

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If the area is 27 meters & 6 meters is the height what is the length ?

bezimeni [28]

Area= legnth times width
or sometimes
area=legnth times height
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area=27
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3 years ago

. What is 7/10 as a percent?

iogann1982 [59]

Answer:

70%

Step-by-step explanation:

5/10. 50%

6/10. 60%

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9/10. 90%

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2 years ago

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Tom and Becky can paint Jim's fence together in 12 hours. If all people paint at the same rate, how many hours would it take to

Delvig [45]

Answer: 8 hours

Step-by-step explanation:

Let x be the time taken by each person to paint the fence.

Given: Tom and Becky can paint Jim's fence together in 12 hours.

Since all people paint at the same rate, then we have the following equation ;-

$\dfrac{1}{x}+\dfrac{1}{x}=\dfrac{1}{12}\\\\\Rightarrow\ \dfrac{2}{x}=\dfrac{1}{12}\\\\\Rightarrow\ x=24$

Thus, the time taken by each person to paint the fence alone = 24 hours

Now, the time taken by all three paint together:-

$\dfrac{1}{t}=\dfrac{1}{24}+\dfrac{1}{24}+\dfrac{1}{24}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{3}{24}\\\\\Rightarrow\ t=\dfrac{24}{3}=8\text{ hours}$

Hence, it would take 8 hours if all three paint together.

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3 years ago

Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in

kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let $y\in (x-\epsilon,x+\epsilon)$ . then we have that $x-\epsilon$ . Hence, it makes sense to define the positive number delta as $\delta=\min\{x+\epsilon-y,y-(x-\epsilon)\}$ (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ , and if we prove this, we are done. To prove it, let $z\in (y-\delta,y+\delta)$ , then $y-\delta$ . First, $\delta \leq y-(x-\epsilon)$ then $-\delta \geq -y+x-\epsilon$ hence $z>y-\delta \geq x-\epsilon$

On the other hand, $\delta \leq x+\epsilon-y$ then $z$ hence $z$ . Combining the inequalities, we have that $x-\epsilon$ , therefore $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ as required.

3 0

3 years ago