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2 years ago

Tony heard that housing expenses should

Mathematics

1 answer:

zzz [600]2 years ago

7 0

Multiply the month;y income by the percentage:

8300 x 0.28 = 2324

He can spend $2,324 a month.

You might be interested in

Evaluate the expression for the given value of x 7x + 8 for x = 2

Anit [1.1K]

Answer:

Step-by-step explanation:

Since x = 2, we can tell that x is equal to 2.

So this is basically asking 7 times 2 plus 8

7(2) + 8 = ?

14 + 8 = 22

Hope this helps!

4 0

2 years ago

Read 2 more answers

Evaluate 3^2 + (5 − 2) ⋅ 4 − 6 over 3. 19 16 46 24

Ludmilka [50]

3^2 +(5-2)* 4-6/3
Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction
3^2+3*4- 6/3
9+3*4- 6/3
9+12- 6/3
9+12-2
9+10
19
So your answer is 19.

8 0

2 years ago

77+ 2(3x – 5) = 8 – 3(2x + 1) 78 2 + 3(2 -7) – 0 - 13 I 1).

nika2105 [10]

Answer:

-31/6

Step-by-step explanation:

77+2(3x-5)=8-3(2x+1)

77+6x-10=8-6x-3

77-10+6x=8-3-6x

67+6x=5-6x

67+6x-(-6x)=5

67+6x+6x=5

67+12x=5

12x=5-67

12x=-62

x=-62/12

simplify

x=-31/6

3 0

2 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

2 years ago

Ruchi and Sindhu went shopping. Sindhu had twice the amount of money as Ruchi.Ruchi purchased utilities for ₹60. Sindhu purchase

Marat540 [252]

Answer:

50¥

Step-by-step explanation:

3 0

2 years ago