Answer:
Answer to the following question is as follows;
Step-by-step explanation:
Given:
Amount invested by Mr. Mohit = Rs. 50,00,000
Computation:
Books of (...... LTD)
Journal entries
Date Particular Debit Credit
March 1 Cash A/C Dr. 50,00,000
To Capital A/C Cr. 50,00,000
(Being Amount invested in new business)
Answer:
x=2 and y=−6
sorry this is pretty long, I did not know if you needed the steps or not
Step-by-step explanation:
−2y−10=x;−10x−y=−14
Solve−2y−10=x for x
−2y−10=x
−2y−10+−x=x+−x
−x−2y−10=0
−x−2y−10+2y=0+2y
−x−10=2y
−x−10+10=2y+10
−x=2y+10
-x/-1=2y+10/-1
x=−2y−10
Substitute−2y−10 for x in−10x−y=−14
−10x−y=−14
−10(−2y−10)−y=−14
19y+100=−14
19y+100+−100=−14+−100
19y=−114
19y/19=-114/19
y=-6
Substitute−6 for y in x=−2y−10
x=−2y−10
x=(−2)(−6)−10
x= 2
x=2 and y=−6
Answer: You simply need to match each fraction to where they belong
Step-by-step explanation:
Let x = 32.323232…
Then 100x = 3232.323232…
It follows that
100x - x = 3232.323232… - 32.323232…
99x = 3200
x = 3200/99
