Answer:

Step-by-step explanation:


Used PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
First Power, next Addition
Answer:
Hundreths 3 is in the hundreths
Step-by-step explanation:
Answer:
Model B has 6 shaded sections
Step-by-step explanation:
The question is not complete. The complete question should be in the form:
Victor has 2 fraction models. Each is divided into equal sized sections the models are shaded to represent the same fraction. Model A is divided into 6 sections and 3 sections are shaded. Model B is divided into 12 sections. What do you know about the number of sections shaded in Model B? Explain your answer.
Solution:
The fraction modeled by model A is given by the ratio of shaded sections to the total number of sections.
That is Fraction of model A = number of shaded sections / total number of sections.
Hence:
Fraction of model A = 3 / 6
Since model B and Model A are equivalent, the number of shaded sections in Model A is given by:
number of shaded sections in model B/ total number of sections in model B = Fraction of model A
number of shaded sections in model B / 12 = 3 / 6
number of shaded sections in model B = 12 * 3/6
number of shaded sections in model B = 6
1 yard = 3 feet
2.5×18=45 feet
45÷3= 15 yards
Answer:
Given sides 12, 16 and 20 can be the sides of right triangle.
Step-by-step explanation:
Sides of right triangle always follow the Pythagoras theorem.
i.e 
For the given Lengths 7, 40 and 41
We need to check if


That means, 
hence 7,40 and 41 can not be the sides of right triangle.
Next,
Given sides 12,16 and 20.
Again follow the similar process used in the above problem.

Therefore given sides 12,16 and 20 can be the sides of right triangle.