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Valentin [98]
2 years ago
15

Given y=x^2 how would the graph of y=x^2+4 differ?

Mathematics
1 answer:
satela [25.4K]2 years ago
6 0
A) The graph will move up by 4 units
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The path of a roller coaster over a particular length of track can be represented by a quadratic function f, where f(x) represen
alexgriva [62]
The roller coaster could be represented by the function for Choice D.

If you were to graph this function, you would find that the zeros (x-intercepts) of the function are at the points of -2 and 1. Those are the needed points in the problem.

Since this is a parabola that opens upward, the parabola must be below the axis (or support bar) between those values.
8 0
3 years ago
OH NO!!! Madeleine’s data has been corrupted, again! Using the incomplete data file below, which she was able to recover from he
-Dominant- [34]

Answer:

a. N=25

b. X[bar]= 60.52

c. Y[bar]= 106.72

d. SSx= 115.24

e. ∑X*∑Y = 4036684

f. SSxy= 202020.3296

g. √(SSx*SSy)= 449.46

Step-by-step explanation:

Hello!

Using the attached data you need to calculate some statistics.

a) N

The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.

b.

The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52

∑X is listed in the second table.

c.

The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72

∑Y is listed in the second table.

d.

Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24

e.

∑X*∑Y =1513*2668= 4036684

f.

SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296

g.

√(SSx*SSy)= √(115.24*1753)= 449.46

I hope you have a SUPER day!

3 0
2 years ago
True or false by definition a simple random sample of size n
Sophie [7]
True

I hope I helped you out
7 0
3 years ago
A 4​-ft vertical post casts a 12​-in shadow at the same time a nearby cell phone tower casts a 122​-ft shadow. How tall is the c
zepelin [54]

Answer:

the cell phone tower is 488 ft

Step-by-step explanation:


change 12 in = 1ft

4ft                            x ft

------------------- =   ----------------

1ft  shadow           122 ft shadow


using cross products

4 * 122 = 1 * x

488 = x

3 0
2 years ago
If....................
kobusy [5.1K]

Answer:

C  - 22

Step-by-step explanation:

Put in '3 ' for 'x' in both of the equations....then multiply the results together

f(3)  = 3 (3)^2 - 5 = 22

g(3) =  -1

22 * -1  = -22

5 0
1 year ago
Read 2 more answers
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