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Valentin [98]
3 years ago
15

Given y=x^2 how would the graph of y=x^2+4 differ?

Mathematics
1 answer:
satela [25.4K]3 years ago
6 0
A) The graph will move up by 4 units
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I mean this. when write 1.
yawa3891 [41]
If the question is 7 x 200+50+6 it equals 1792
4 0
3 years ago
8x + 34. What does X equal
rosijanka [135]

Answer: x=-4.25

Step-by-step explanation:

First you put it in to y= mx+b form.

0=8x+34

Then you subtract 34 from both sides

-34=8x

Then you divide 8 from both sides

Leaving you with

x=-4.25

4 0
3 years ago
A. 40, B.80, C.120, D. 160, or E. 400
Rudik [331]
B: 80

All the sides add up to 20 so adding all four sides make 80
6 0
3 years ago
Read 2 more answers
Which represents the solution set of an any quality 5X-9 greater than 21
Svet_ta [14]

Answer:

The last one

Step-by-step explanation:

5x<30

x<6

Because when you divide by pos+ number

the symbol cannot change.

6 0
3 years ago
In a graphing program, graph the following 4 functions in the same coordinate plane.
9966 [12]

See below for the changes when the exponential function is transformed

<h3>How to determine the effect of a</h3>

The exponential functions are given as:

y = \sqrt x

y = 5\sqrt x

y = 14\sqrt{x

y = -2\sqrt{x

An exponential function of the above form is represented as:

y = a\sqrt{x

See attachment for the graph of the four functions.

<u>When a is large</u>

This is represented by y = 14\sqrt{x

In this case, the curve of the base form y = \sqrt x is vertically stretched and it moves closer to the y-axis

<u>When a is small</u>

This is represented by y = 5\sqrt x

In this case, the curve of the base form y = \sqrt x is vertically stretched and it moves away from the x-axis

<u>When a is negative</u>

This is represented by y = -2\sqrt{x

In this case, the curve of the base form y = \sqrt x is vertically stretched and is reflected across the y-axis.

Read more about function transformation at:

brainly.com/question/26896273

#SPJ1

5 0
2 years ago
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