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Lina20 [59]
3 years ago
5

How do you write 0.000056 in scientific notation?

Mathematics
1 answer:
anygoal [31]3 years ago
8 0
5.6 × 10^-5 = 0.000056
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The temperature changed from 7°f at 6pm to -5°f at midnight. What was the difference between the high an low temperatures? Whats
Ronch [10]

Answer:

Difference between high and low temperatures: 12°F

Average change in temperature per hour: 2°F

Step-by-step explanation:

The difference between high and low temperatures was: 7 - (-5) = 12 (°F)

Midnight is 12am, so 6pm to midnight is 6 hours.

The average change in temperature per hour is: 12 / 6 = 2 (°F)

7 0
3 years ago
Find the first six terms of the sequence. a1 = 1, an = 4 • an-1
maksim [4K]
\bf \begin{array}{ccllll}
n&term&value\\
---&-----&-----\\
1&a_1&1\\
2&a_2&4\cdot a_{2-1}\\
&&4\cdot a_1\\
&&4\\
3&a_3&4\cdot a_{3-1}\\
&&4\cdot a_2\\
&&16\\
4&a_4&4\cdot a_{4-1}\\
&&4\cdot a_3\\
&&64\\
5&a_5&4\cdot a_{5-1}\\
&&4\cdot a_4\\
&&256\\
6&a_6&4\cdot a_{6-1}\\
&&4\cdot a_5\\
&&1024
\end{array}
3 0
3 years ago
9 + 9h<br> =<br> 10h + 2 is this infinite solution
Kamila [148]

Answer:

no, h=7

Step-by-step explanation:

9+9h = 10h+2

9=h+2

7=h

7 0
2 years ago
Which table shows a non linear relationships between x and y
bazaltina [42]

Answer:

both of them thats the answer

Step-by-step explanation:

7 0
3 years ago
The new ointment was applied to four locations, and a control was applied to the other four. How many different choices were the
lubasha [3.4K]

Answer:

there are 70 possible choices for the four locations to apply the new ointment

Step-by-step explanation:

Since we have a total of 8 locations ( 4 to the new ointment and 4 to the control) ,  each one can be chosen and since the order of the locations that are chosen for the new ointment is not relevant  , then we know that the number of choices is given by the number of combinations of 4 elements in 8

number of combinations = 8 possible locations to the first ointment * 7 possible locations to the second ( since the first one was already located) * 6 to the third * 5 locations for the fourth / number of times the same combination is repeated ( the same locations but in different positions) = 8*7*6*5 / (4 possible positions for the first ointment* 3 possible positions to the second ointment (since the first one was already located * 2 possible positions of the third * 1 possible position of the fourth)

therefore

number of combinations = 8*7*6*5/(4*3*2*1 ) = 8!/((8-4)!*4!) = 70 possible combinations

thus there are 70 possible choices for the four locations to apply the new ointment

6 0
3 years ago
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