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Lina20 [59]
3 years ago
5

How do you write 0.000056 in scientific notation?

Mathematics
1 answer:
anygoal [31]3 years ago
8 0
5.6 × 10^-5 = 0.000056
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On a piece of paper, graph Y = 2x - 3, what is the answer?
Anvisha [2.4K]
First, determine y-intercept and x-intercept of the line
# y-intercept (when x = 0)
y = 2x - 3
y = 2(0) - 3
y = 0 - 3
y = -3

# x-intercept (when y = 0)
y = 2x - 3
0 = 2x - 3
2x - 3 = 0
2x = 3
x = 3/2
x = 1.5

Second, put y-intercept and x-intercept on cartesian plane, then connect the intercepts
See image attached

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4 years ago
Show step by step for equation -8/3x + 4(x + 9/4) = -2/3(x + 12/8) + 3
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3 years ago
sector with a radius 18cm has an area of 234pie cm2. What is the central angle measure of the sector in degrees?
Pani-rosa [81]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
5(u+5)+p(u+5) in factored form
ANTONII [103]
<span>5(u+5)+p(u+5) = (u+5)(5+p)</span>
6 0
3 years ago
How do you solve this question?
aliya0001 [1]
We can use the quadratic formula to solve this problem.

\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

You've already listed the values for 'a', 'b', and 'c', so just plug them into the formula:

\sf x=\dfrac{-(-12)\pm\sqrt{(-12)^2-4(4)(9)}}{2(4)}

Simplify:

\sf x=\dfrac{12\pm\sqrt{144-4(4)(9)}}{8}

Multiply:

\sf x=\dfrac{12\pm\sqrt{144-144}}{8}

Subtract:

\sf x=\dfrac{12\pm\sqrt{0}}{8}

Take the square root:

\sf x=\dfrac{12\pm 0}{8}

It doesn't matter if you add or subtract something with 0, you'll end up with the same thing, so we have:

\sf x=\dfrac{12}{8}\rightarrow\boxed{\sf 1\dfrac{1}{2}}
8 0
4 years ago
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