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marusya05 [52]
3 years ago
5

Jane solved an equation and got a solution of X=3. The teacher then asked what the value of 6X would be. Which of the answer is

correct? A 6X=24 B 6X=6 C 6X=3 D 6X=18
Mathematics
1 answer:
weeeeeb [17]3 years ago
6 0

If the solution of x is 3, then the solution of 6x would be 18, because 3*6=18. :)

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Find the sum of the geometric sequence. (7 points) 4/3, 8/3, 16/3, 32/3, 64/3
Arisa [49]
The sum is 41.22 because first you turn all of the fractions into decimals and then it’s easier to add them all together all at once.
7 0
3 years ago
Help pls it’s urgent
ArbitrLikvidat [17]

Answer:

S = 2π(4)^2 + 2π(4)(16)

Step-by-step explanation:

The surface area of a cylinder can be found using this equation: 2(πr^2) + 2(πrh). Therefore the answer would be the first one: S = 2π(4)^2 + 2π(4)(16)

6 0
3 years ago
Would the graph of the following function be discrete or continuous? <br><br> y = 15 + 3x
yanalaym [24]
The other person is right
6 0
2 years ago
Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2
Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

\longrightarrow cos2\phi = cos^2\phi - sin^2\phi

Therefore ,

\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}

And we are done !

\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

\longrightarrow cos(x + x )

As we know that ,

\longrightarrow cos(y + z )= cosy.cosz -  siny.sinz

So that ,

\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)

On simplifying,

\longrightarrow cos(x+x) = cos^2x - sin^2x

Hence,

\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}

\rule{200}{4}

7 0
2 years ago
Adding school fairest 20% of the people are under 16 years old one third of the people remaining are teachers if there are 21 te
dedylja [7]
<span>In the fairest school 20% are below 16 years old
1/3 are teachers which is equals to = 21
Let’s start solving:
=> 1/3 of 100% = ( 100 / 3 = 33.33% )
thus 33.33% = 21
=> 21 x 3 = 63, is the total number of people in the school.
Let’s try solving the number of people below 16 years old
Then there are 20% of it:
=> 63 * .20 = 12.6
Thus, there are around 13 people who are 16 years old younger.</span>



4 0
3 years ago
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