( 7, 10.5 )
<em>Solution:
</em><em />
y = 2x - 3.5
x - 2 y = -14
Plug the first equation into the second equation like so;
x - 2 ( 2x - 3.5 ) = -14
Distribute -2 to 2x and -3.5
Your equation should now look like this:
x - 4x + 7 = -14
You want common numbers to be in the same side so you subtract 7 from both sides
x - 4x + 7 - 7 = -7 - 14
Now simplify both sides
x - 4x = -3x
- 7 - 14 = -21
In order to solve for x you need to get x by itself, so you divide both sides by -3
-3x / -3 = x
-21 / -3 = 7
x = 7
In order to solve for y you need to plug x in
(You can plug it into either equation, but I'm plugging it into the first one)
y = 2 (7) - 3.5
y = 14 - 3.5
y = 10.5
Just add 12 m 38 cm with 4 m 99 cm.
Answer: 17 m 37 cm
D. (-8,-7) Simplifying<span>y + -8 = 4(x + 7)
Reorder the terms:
-8 + y = 4(x + 7)
Reorder the terms:
-8 + y = 4(7 + x)
-8 + y = (7 * 4 + x * 4)
-8 + y = (28 + 4x)
Solving
-8 + y = 28 + 4x
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '8' to each side of the equation.
-8 + 8 + y = 28 + 8 + 4x</span>
Answer:
yes
Step-by-step explanation:
hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -7 and b = -1 (Center at: A(-7,-1) )
r = AP.... P(8,7)
r² = (AP)²
r² = (8+7)² +(7+1)² =225+64=289 ...... so : r = 17
an equation of the circle that satisfies the stated conditions.
Center at </span></span>A(-7,-1), passing through P(8, 7) is :
(x+7)² +(y+1)² = 289
The point (-15,y ) <span>lies on this circle : (-15+7)² +(y+1)² = 289....(subsct : x= -15)
(y+1)² = 225
(y+1)² = 15²
y+1 = 15 or y+1 = -15
y = 14 or y = -16
you have two points : (-15,14) , (-15, -16)</span>
