Answer:
The recombination frequency between two genes exhibits a positive correlation with the distance between them, that is, farther they are, and more will be the chance of recombination. Thus, recombination frequency is used to signify distance among the two genes, for example, 1 percent recombination frequency demonstrates distance of 1 map unit.
Let us consider that the heterozygous female of genotype AaBb can generate four kinds of gametes, that is, AB, Ab, aB and ab. Of these, the two gametes are the outcomes of recombination, or it can be said that 50 percent are recombinants. Thus, it can be concluded that in case of two linked genes, the maximum probable recombination frequency is 50 percent.
This shows that any genes, which are distant than 50 map units will function as unlinked and will function as if they were on distinct chromosomes, and the frequency of recombinant frequency will be 50 percent.
In the given question, it is given that the map distance between the two genes is 80 map units, that is, more than 50 map units. The maximum probable recombinant offspring will be 50 percent of the entire offspring.
I believe passive transport is a form of diffusion. And it doesn't require any energy unlike active transport.
Change the pH and the enzyme<span> stops working. Increasing the temperature to 60°C will cause a permanent change to the shape of the active site. This is why </span>enzymes<span> stop working when they are heated. We say they have become </span>denatured<span>.</span>
Explanation:
it is systematic desensitization.
The first is ture the second false the three is ture 4 ture 5 false 6 ture 7 false 8 ture 9 ture 10 false
