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4 years ago

Convert 80mg to kg show work

Physics

1 answer:

spin [16.1K]4 years ago

7 0

Your answer is 0.00008 kg.

80 mg / 1000000

= 0.00008 kg

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PLS HELP, WILL GIVE BRAINLIEST

PtichkaEL [24]

Answer:

Explanation:

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5 0

3 years ago

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Name the 9 types of energy

Ugo [173]

Hello There!

-Energy Is The Ability To Do Work-

Energy comes into different forms but they can all be placed in two different categories. These categories are "potential" which means stored energy and energy of position and "kinetic" which is the energy of motion.

POTENTIAL ENERGY Stored energy and the energy of position

CHEMICAL ENERGY Energy in the bonds of atoms and molecules

MECHANICAL ENERGY Energy stored in objects by tension

NUCLEAR ENERGY Energy stored in the nucleus of an atom

GRAVITATIONAL Energy that is stored in an object's height

ELECTRICAL ENERGY Delivered by tiny charged particles called electrons

KINETIC ENERY The energy of motion

THERMAL ENERGY The vibration and movement of atoms and molecules in substances.

RADIANT ENERGY Electromagnetic energy that travels in waves

6 0

4 years ago

An electron is in a vacuum near Earth's surface and located at y = 0 m on a vertical y axis. At what value of y should a group o

Bingel [31]

Answer:

the bunch of 23 electrons must be placed on y axis at coordinate y = - 24.35 m.

Explanation:

As we know that the gravitational force on electron at y = 0 is counter-balanced by the weight of the electron

So we have

$\frac{kq_1q_2}{r^2} = mg$

here we have

$q_1 = e$

$q_2 = 23 e$

$m = 9.11 \times 10^{-31} kg$

also we know that

$e = 1.6 \times 10^{-19} C$

so we will have

$\frac{(9\times 10^9)(1.6 \times 10^{-19})(23\times 1.6 \times 10^{-19})}{r^2} = (9.11 \times 10^{-31})(9.81)$

$\frac{5.3 \times 10^{-27}}{r^2} = 8.94 \times 10^{-30}$

$r = 24.35 m$

so the bunch of 23 electrons must be placed on y axis at coordinate y = - 24.35 m.

7 0

3 years ago

A wire of resistance 5.9 Ω is connected to a battery whose emf ε is 4.0 V and whose internal resistance is 1.2 Ω. In 2.9 min, ho

dexar [7]

Answer:

a) 390J

b) 322J

c) 68J

Explanation:

We need to calculate the power given by the battery. the power is given by:

$P=V*I\\I=\frac{V}{R}\\I=\frac{4}{5.9+1.2}\\I=0.56A\\P=2.24W$

Watts is J/s so:

$E=P*t\\E=2.24\frac{J}{s}*2.9min*(60\frac{s}{min})=390J$

The thermal energy in the wire is given by:

$E_w=P_w*t\\P_w=I^2*R_w=0.56^2*5.9=1.85W\\E_w=1.85\frac{J}{s}*2.9min*(60\frac{s}{min})=322J$

And the the dissipated thermal energy in the battery will be the remainig energy:

$E_b=E-E_w\\E_b=390-322=68J$

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4 years ago

Please help me with thus question (picture) D:

IrinaVladis [17]

well thanks for the Information

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3 years ago

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