((2x^2+5x-3)/(1-4x^2))/((x^3-9x)/(x^4-6x^3+9x^2)) FIND X

1 answer:

6 0

You can't find a value of x since there is no equal sign. This is not an equation. It is just an expression, so you can't solve it for x.

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17. The length of a rectangle is 12 in, and the perimeter is 56 in. Find the width of the rectangle.

Ivahew [28]

Answer:

Step-by-step explanation:

P = 2(L + W)

P = 56

L = 12

now sub...we are looking for w

56 = 2(12 + W)

56 = 24 + 2W

56 - 24 = 2W

32 = 2W

32/2 = W

16 = W <==== the width is 16 inches

check...

P = 2(L + W)

56 = 2(12 + 16)

56 = 2(28)

56 = 56 (correct)

4 0

3 years ago

Triangle DEF (not shown) is similar to ABC shown, with angle B congruent to angle E and angle C congruent to angle F. The length

Bezzdna [24]

Answer:

Area of ΔDEF is $45\ cm^2$ .

Step-by-step explanation:

Given;

ΔABC and ΔDEF is similar and ∠B ≅ ∠E.

Length of AB = $2\ cm$ and

Length of DE = $6\ cm$

Area of ΔABC = $5\ cm^2$

Solution,

Since, ΔABC and ΔDEF is similar and ∠B ≅ ∠E.

Therefore,

$\frac{Area\ of\ triangle\ 1}{Area\ of\ triangle\ 2} =\frac{AB^2}{DE^2}$

Where triangle 1 and triangle 2 is ΔABC and ΔDEF respectively.

If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.

$\frac{5}{Area\ of\ triangle\ 2} =\frac{2^2}{6^2}\\ \frac{5}{Area\ of\ triangle\ 2}=\frac{4}{36}\\ Area\ of\ triangle\ 2=\frac{5\times36}{4} =5\times9=45\ cm^2$