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AURORKA [14]
3 years ago
8

Suppose a gas starts with a volume of 4.52L, temperature of 23 C, and pressure of 102,00 Pa. If the volume changes to 4.83L and

a temperature of -12C what is the new temperature of the gas
Chemistry
1 answer:
ivanzaharov [21]3 years ago
8 0

Answer:

The answer to your question is     P2 = 84.16 kPa

Explanation:

Data

Volume 1 = V1 = 4.52 L            Volume 2 = V2 = 4.83 l

Pressure 1 = P1 = 102 kPa        Pressure 2 = P2 = ?

Temperature 1 = T1 = 23°C      Temperature 2 = T2 = -12°C

Process

1.- Convert the temperature to °K

Temperature 1 = 23 + 273 = 296°K

Temperature 2 = -12 + 273 = 261°K

2.- Use the Combined Gas law to solve this problem

                  P1V1/T1 = P2V2/T2

-Solve for P2

                  P2 = P1V1T2 / T1V2

-Substitution

                  P2 = (102)(4.52)(261) / (296)(4.83)

-Simplification

                  P2 = 120331.44 / 1429.68

-Result

                  P2 = 84.16 kPa

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Contact [7]

Answer:

The answer to your question is below

Explanation:

Factors that affect the rate of a chemical reaction

- Temperature        If the temperature increases the rate of reaction increases.

- Concentration     The reaction will move where there less concentration it could be to the reactants of products.

- Particle size         The lower the particle size the higher the rate of reaction.

- Catalyst                 Catalyzers accelerate the rate of reaction

- Pressure                The reaction will move where there are fewer molecules.

3 0
3 years ago
How many moles of carbon dioxide gas should be produced when 10.0 g of C2H6 are combusted at STP?
Finger [1]

Answer:

                    0.665 moles of CO₂

Explanation:

                     The balance chemical equation for the combustion of Ethane is as follow:

                            2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

Step 1: <u>Calculate moles of C₂H₆ as;</u>

                              Moles  =  Mass  /  M.Mass

Putting values,

                              Moles  =  10.0 g / 30.07 g/mol

                              Moles  =  0.3325 moles

Step 2: <u>Calculate Moles of CO₂ as;</u>

According to balance chemical equation,

                    2 moles of C₂H₆ produced  =  4 moles of CO₂

So,

             0.3325 moles of C₂H₆ will produce  =  X moles of CO₂

Solving for X,

                      X  =  0.3325 mol × 4 mol ÷ 2 mol

                      X = 0.665 moles of CO₂

3 0
3 years ago
Mount Everest rises to a height of 8,850 m above sea level. At a base camp on the mountain the atmospheric pressure is measured
yan [13]

Answer:

Water will boil at 76^{0}\textrm{C}.

Explanation:

According to clausius-clapeyron equation for liquid-vapor equilibrium:

                                         ln(\frac{P_{2}}{P_{1}})=\frac{-\Delta H_{vap}^{0}}{R}[\frac{1}{T_{2}}-\frac{1}{T_{1}}]

where, P_{1} and P_{2} are vapor pressures of liquid at T_{1} (in kelvin) and T_{2} (in kelvin) temperatures respectively.

Here, P_{1} = 760.0 mm Hg, T_{1} = 373 K, P_{2} = 314.0 mm Hg

Plug-in all the given values in the above equation:

                          ln(\frac{314.0}{760.0})=\frac{-40.7\times 10^{3}\frac{J}{mol}}{8.314\frac{J}{mol.K}}\times [\frac{1}{T_{2}}-\frac{1}{373K}]

                       or, T_{2}=349 K

So, T_{2}=349K=(349-273)^{0}\textrm{C}=76^{0}\textrm{C}

Hence, at base camp, water will boil at 76^{0}\textrm{C}

6 0
3 years ago
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Answer:

Ozone is a molecule with three oxygen molecules.It is in the upper atmosphere and it protects living organisms by keeping UV rays from reaching the earth's surface. Ozone (O3) is a triatomic, molecule, consisting of three oxygen atoms. ... O3 is the formula for ozone. It has three oxygen atoms.

Explanation:

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3 years ago
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Answer:

Neutron

Explanation:

3 0
2 years ago
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