Complete question:
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.
Answer:
The magnitude of q for the process 568 J.
Explanation:
Given;
change in internal energy of the gas, ΔU = 475 J
work done by the gas, w = 93 J
heat added to the system, = q
During gas expansion process, heat is added to the gas.
Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.
ΔU = q - w
q = ΔU + w
q = 475 J + 93 J
q = 568 J
Therefore, the magnitude of q for the process 568 J.
Answer:
Quantitative observation is an objective collection of data which is primarily focused on numbers and values.
Answer:
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Explanation:
Answer:
Explanation:
The mass of an atom is dependent on its number of protons and neutrons. Electrons have mass, but are too light in comparison to protons and neutrons to contribute towards the overall mass. Their relative mass is about 1/1840 compared to 1 for protons and neutrons, and therefore are not counted in the mass.
Hope this helped!
