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2 years ago

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Water and ammonium nitrate (NH4NO3) react in an endothermic reaction in a beaker. What would you expect to observe during this r

eaction?
The beaker will get colder.
The reaction will give off light.
The products will be gaseous.
The reactants will boil.

1 answer:

maksim [4K]2 years ago

3 0

Answer:

The beaker will get colder

Explanation:

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How many molecules are in 1 mole of H2O molecules?

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Answer:don’t know

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3 years ago

Together, the protons and neutrons are called what?

mario62 [17]

I think B. is the correct answer i hope i helped

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3 years ago

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Ryan and Abigail are conducting an experiment. They place six ice cubes into a beaker and find the combined mass. They allow the

JulijaS [17]

The mass of the ice cubes and the water will be equal because the same amount of matter is in the beaker.

Matter is anything that has mass and occupy space. All substances are composed of matter. According to the law of conservation of mass, matter can neither be created nor destroyed but can be converted from one form to another.

Since mass is the quantity of matter in a substance, the mass of the ice cubes and the water will be equal because the same amount of matter is in the beaker.

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2 years ago

The force of 20 N acts upon a 5kg block. What is the acceleration of the block?

charle [14.2K]

Answer:

<h2>The answer is 4 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

where

a is the acceleration

f is the force

m is the mass

From the question

f = 20 N

m = 5 kg

We have

$a = \frac{20}{5} \\$

We have the final answer as

<h3>4 m/s²</h3>

Hope this helps you

8 0

2 years ago

Be sure to answer all parts. calculate δg ocell for the reaction between cr(s) and cu2+(aq). e ocell = 1.08 j/c. enter your answ

Mademuasel [1]

Answer:

$\boxed{-6.29 \times10^{5}\text{ J}}$

Explanation:

Step 1. Determine the cell potential

<u> E°/V </u>

2×[Cr ⟶ Cr³⁺ + 3e⁻] 0.744 V

<u>3×[Cu²⁺ + 2e⁻ ⟶ Cu] </u> <u>0.3419 V </u>

2Cr + 3Cu²⁺ ⟶ 3Cu + 2Cr³⁺ 1.086 V

Step 2. Calculate ΔG°

$\Delta G^{\circ} = -nFE_{\text{cell}}^{^{\circ}} = -6 \times 96 485 \times 1.086 = \text{-629 000 J}\\\\= \boxed{-6.29 \times10^{5}\text{ J}}$

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2 years ago