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3 years ago

How does magnesium and nitric acid react? (Observations)

1 answer:

5 0

It depends on the strength of the nitric acid. With dilute acid magnesium nitrate and hydrogen gas is formed. The gas reacts violently with a naked flame.

With concentrated nitric acid a violent reaction occurs and lots of reddish brown fumes of nitrogen oxides (NO and NO2) are produced.

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When heat move in a gas or liquid, warm matter rise and cold matter sinks, creating currents. which type of heat transfer is thi

ch4aika [34]

I believe it is convection

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3 years ago

Cho m gam FeO tác dụng hết với dung dịch H2SO4, thu được 200 ml dung dịch FeSO4 1M. Giá trị của m là

BaLLatris [955]

Answer: The mass of $FeO$ required is 14.37 g

Explanation:

Molarity is calculated by using the equation:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}$ ......(1)

We are given:

Molarity of iron (II) sulfate = 1 M

Volume of solution = 200 mL = 0.200 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$\text{Moles of }FeSO_4=(1mol/L\times 0.200L)=0.200mol$

The chemical equation for the reaction of FeO with sulfuric acid follows:

$FeO+H_2SO_4\rightarrow FeSO_4+H_2O$

By stoichiometry of the reaction:

If 1 mole of iron (II) sulfate is produced by 1 mole of FeO

So, 0.200 moles of iron (II) sulfate will produce = $\frac{1}{1}\times 0.200=0.200mol$ of FeO

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We know, molar mass of $FeO$ = 71.84 g/mol

Putting values in above equation, we get:

$\text{Mass of }FeO=(0.200mol\times 71.84g/mol)=14.37g$

Hence, the mass of $FeO$ required is 14.37 g

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3 years ago

(T) (F) The Great Decoupling means that well-being and wealth can increase while the use of resources and production of pollutio

Alex787 [66]

I think is true i took the test but im not sure what i put! Correct me if wrong

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3 years ago

Look back at your data and your regression equation. (Sample data is shown to the right, with X= pressure and Y=volume.) click a

laiz [17]

Select the block of cells to be included in the scatter plot by clicking and dragging, then from the Insert ribbon under Chart drop down the Scatter or Bubble menu and select Scatter. A chart will appear on the spreadsheet.

To set up a scatter plot in Excel, enter the pairs of data in two columns with each value of a pair on the same row. By default, Excel considers the column on the left to contain the horizontal (X) values and the column on the right to contain the vertical (Y) values.

If you click on the + sign at the upper right of the chart, a list of checkboxes will appear. Check Axes, Axis Titles, and Trendline. Uncheck everything else. You should edit the Axis Titles to include the name of the factor and any units associated with it. Double-click on the Axis numbers to bring up the Format Axis dialog, then click on the bar-graph icon to access Axis Options. Set the bounds and units appropriately and set the tick marks to something sensible.

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3 years ago

Calculate the theoretical carbonaceous and nitrogenous oxygen demand for:

serg [7]

Answer:

The correct answer is 129 mg and 232 mg.

Explanation:

Theoretical carbonaceous oxygen demand:

The reaction will be,

C₂H₆O₂ + 5/2 O₂ ⇒ 2CO₂ + 3H₂O

Thus, for one mole of C₂H₆O₂ (ethylene glycol), 2.5 moles of O₂ is needed.

The molecular mass of ethylene glycol is 62 grams per mole.

The given mass of ethylene glycol is 100 mg or 0.1 grams

The moles of ethylene glycol will be,

Moles = Weight/Molecular mass

= 0.1/62 = 1.613 × 10⁻³ mol

For 1.613 × 10⁻³ mol, the moles of O₂ will be,

= 2.5×1.613×10⁻³

= 4.0.×10⁻³ × 32mol

= 0.129 grams or 129 mg.

The theoretical nitrogenous oxygen demand is:

The reaction will be,

2NH₃-N + 9/2O₂ ⇒ 4HNO2 + H₂O

Thus, for 2 moles of NH₃-N, 4.5 moles of O₂ is needed,

Therefore, for 1 mol of NH₃-N, the oxygen required will be,

= 4.5/2 = 2.25 mol

The given mass of NH₃-N is 100 mg, the moles of NH₃-N will be,

Moles = 100×10⁻³/31 = 3.225 × 10⁻³ mol (The molecular mass of NH₃-N is 31 gram per mole)

The moles of O₂ is 2.25 × 3.225 × 10⁻³ = 7.258 × 10⁻³ mol.

Now the mass of O2 will be,

= 7.258 × 10⁻³ × 32

= 0.232 grams

= 232 mg

5 0

3 years ago