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mina [271]
4 years ago
11

A portrait without its frame has a height 1.5 times its width w, in inches. The width of the frame is 3 inches. Which of the fol

lowing is an expression for the area of the framed portrait in terms of w

Mathematics
1 answer:
ICE Princess25 [194]4 years ago
5 0

Answer:

Area = 1.5w^2+15w+36

Step-by-step explanation:

Let the width of portrait be 'w'

Given:

Height of portrait without frame (h) = 1.5 times its width = 1.5w

Width of the frame is 3 inches on all sides.

Area of the framed portrait is the total area of the portrait plus the area of the frame.

The figure representing the above scenario is shown below.

From the figure, area of rectangle ABCD is the area of the framed portrait.

From the figure,

AB = 3 + w + 3 = w + 6

BC = 3 + h + 3 = h + 6 = 1.5w + 6

Now, area of the rectangle ABCD is given as the product of the length AB and width BC. Therefore,

Area=AB\times BC\\\\Area=(w+6)(1.5w+6)\\\\Area=(w\times 1.5w)+(w\times 6)+(6\times 1.5w)+(6\times 6)\\\\Area=1.5w^2+6w+9w+36\\\\Area=1.5w^2+15w+36

Therefore, the expression for the area of the framed portrait in terms of the width 'w' is given as:

Area = 1.5w^2+15w+36

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Step-by-step explanation:

Here, it can work well to consider the seeds from the group of 18 that are NOT selected to be part of the group of 15 that are planted.

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We are interested in the number of ways exactly one of the 10 parsley seeds can be chosen NOT to plant. For each of the 10C1 = 10 ways we can ignore exactly 1 parsley seed, there are also 8C2 = 28 ways to ignore two non-parsley seeds from the 8 that are non-parsley seeds.

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A devastating freeze in California's Central Valley in January 2007 wiped out approximately 75% of the state's citrus crop. It t
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The relationship between the percentage of frozen citrus crop, and the cost of box of oranges is an illustration of a linear function.

  • <em>The linear equation of the function is: </em>g(P) = 22.9P+7<em>.</em>
  • <em>The inverse function is: </em>g^{-1}(c) = \frac{1}{22.9}(c - 7)<em> .</em>
  • <em>A practical domain is from 0% to 100%</em>
  • <em>A practical range is from 7 to 29.9 </em>

<u>A. Input quantity</u>

The input quantity is the percentage of frozen citrus crop

<u />

<u>B. Output quantity </u>

The output quantity is the cost of box of oranges

<u>C. The linear function</u>

We have:

(P_1,c_1) = (20\%,11.58)\\(P_2,c_2) = (80\%,25.32)

<em>Calculate the slope of the function</em>

m = \frac{c_2 - c_1}{P_2 - P_1}

m = \frac{25.32 - 11.58}{80\%-20\%}

m = \frac{13.74}{60\%}

m = 22.9

<em>The linear equation is calculated as follows:</em>

c -c_1 = m(P-P_1)

c -11.58= 22.9(P-20\%)

c-11.58 = 22.9P-4.58

<u>D. Rewrite as y = mx + b</u>

We have:

c-11.58 = 22.9P-4.58

Collect like terms

c = 22.9P - 4.58 + 11.58

c = 22.9P+7

<em>The function is:</em>

g(P) = 22.9P+7

<u>E. A practical domain</u>

The domain is the possible values of P.  Because P is a percentage, its possible values are 0% to 100%.

The domain of the function is: [0\%,100\%]

<u>F. A practical range</u>

When P = 0%

c = 22.9 \times 0\% + 7 = 7

When P = 100%

c = 22.9 \times 100\% + 7 = 29.9

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G. The meaning of g^{-1}(12)

The inverse function of g(P) is g^{-1}(P)

So:

g^{-1}(12) is the percentage of frozen citrus crop, when the cost is $12.

<u>H. The inverse formula</u>

We have:

c = 22.9P+7

Subtract 7 from both sides

c - 7 = 22.9P

Make P the subject

P = \frac{1}{22.9}(c - 7)

So, the inverse formula is:

g^{-1}(c) = \frac{1}{22.9}(c - 7)

Substitute 12 for c

g^{-1}(12) = \frac{1}{22.9}(12 - 7)

g^{-1}(12) = \frac{1}{22.9} \times 5

g^{-1}(12) = 22\%

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