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antoniya [11.8K]
2 years ago
13

(I am giving branlest) plz help

Mathematics
2 answers:
svlad2 [7]2 years ago
6 0

Answer:

the answer is a

Step-by-step explanation:

2/6=1/3 therefore 4/6+1/3=6/6

Rudiy272 years ago
5 0

Answer:

huhhh??

Step-by-step explanation:

i didn't unxerstand the question

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Hello : 
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Ilia_Sergeevich [38]

Answer:

Sample space= 1, 2, 3, 4, 5, 6

Outcomes= 2, 4, 6

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3 years ago
What is the average rate of change of the function f(x)=2x2+8 over the interval [2, 6]? A 2 B 4 C 12 D 16
Vinil7 [7]

Answer:

D. 16

Step-by-step explanation:

Average rate of change: \frac{f(a) - f(b)}{a-b}

Simply plug in 6 for <em>a</em> and 2 for <em>b</em>

<em />

6 0
3 years ago
Read 2 more answers
Find the magnitude of WX for W(-2, 8, -3) and X(1, 4, -1)
zheka24 [161]

The magnitude of WX is  \sqrt{29}  ⇒ c

Step-by-step explanation:

The magnitude of XY (its length) where,

  • X=(x_{1},y_{1},z_{1})
  • Y=(x_{2},y_{2},z_{2})

is IXYI = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}

∵ W = (-2 , 8 , -3)

∵ X = (1 , 4 , -1)

- To find the magnitude of WX use the formula above

∴ x_{1} = -2 and x_{2} = 1

∴ y_{1} = 8 and y_{2} = 4

∴ z_{1} = -3 and z_{2] = -1

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∵ IWXI = \sqrt{(1--2)^{2}+(4-8)^{2}+(-1--3)^{2}}=\sqrt{9+16+4}

∴ IWXI = \sqrt{29}

The magnitude of WX is  \sqrt{29}

Learn more:

You can learn more about the position of an object in brainly.com/question/10940255

#LearnwithBrainly

8 0
3 years ago
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Write the explicit formula that represents the geometric sequence -2, 8, -32, 128
lora16 [44]
a_{1}=-2 \\  \\ a_{2}=8 \\  \\ q= \frac{a_{2}}{a_{1}}  \\  \\ q= \frac{8}{-2}=-4 \\  \\ a_{n}=a_{1}*q^{n-1} \\  \\ a_{n}=-2*-4^{n-1}
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