Answer : The the partial pressure of the nitrogen gas is 0.981 atm.
The total pressure in the tank is 2.94 atm.
Explanation :
The balanced chemical reaction will be:

First we have to calculate the moles of dimethylhydrazine.
Mass of dimethylhydrazine = 150 g
Molar mass of dimethylhydrazine =60.104 g/mole


Now we have to calculate the moles of
gas.
From the balanced chemical reaction we conclude that,
As, 1 mole of
react to give 3 moles of
gas
So, 2.49 mole of
react to give
moles of
gas
Now we have to calculate the partial pressure of nitrogen gas.
Using ideal gas equation :

where,
P = Pressure of
gas = ?
V = Volume of
gas = 250 L
n = number of moles
gas = 7.47 mole
R = Gas constant = 
T = Temperature of
gas = 
Putting values in above equation, we get:

Thus, the partial pressure of the nitrogen gas is 0.981 atm.
Now we have to calculate the total pressure in the tank.
Formula used :




where,
= total pressure = ?
= partial pressure of nitrogen gas = 0.981 atm
= moles of nitrogen gas = 3 mole (from the reaction)
= total moles of gas = (3+4+2) = 9 mole (from the reaction)
Now put all the given values in the above formula, we get:

Thus, the total pressure in the tank is 2.94 atm.