Answer:
The magnitude of induced emf is 5.4 V
Explanation:
Given:
Magnetic field 
T
Area of loop 
Time take to reduce loop to zero 
sec
To find induced emf we use faraday's law,
Induced emf is given by,
Here minus sign shows lenz law, for finding magnitude of emf we ignore it.
Where 
Put the value of flux and find induced emf,
V
Therefore, the magnitude of induced emf is 5.4 V
Answer:
<em>D. Velocity</em>
Explanation:
<u>Energy Dimensional Analysis</u>
The kinetic energy (K) can be calculated by the formula:
Where:
m = mass of the object
v = speed at which the object moves
Solving for v:
Or, equivalently:
In dimensional terms, the quotient of the square roots of the energy and the mass is equivalent to the dimensions of the velocity (or speed),
D. Velocity
This is a projectile motion problem, so, we use the formula for trajectory:
y =xtanα + gx^2/2v^2(cosα)^2
where
y is the vertical distance (y = 50 m)
x is the horizontal distance (x=90 m)
α is the angle of trajectory; since it levels of HORIZONTALLY, α = 0°
v is the initial velocity
g is the acceleration due to gravity which is 9.81 m/s^2
Substituting to the formula,
50 =90tan(0°) + (9.81)(90)^2/2v^2(cos0°)^2
v = 28.2 m/s
