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3 years ago

What is most likely consequence if a group of living organisms is unable to adapt to changing conditions within the Earth system

Biology

1 answer:

Charra [1.4K]3 years ago

3 0

Answer:

If a group of living organisms is unable to adapt to changing conditions with the earth's system, it shall face extinction.

Explanation:

As time goes by, the earth's systems keep changing, either negatively or positively.

If the earth's temperature decreases then living organisms shall adapt to surviving in cold conditions, they shall for instance grow heavy fur cover on their skin to cover them from the cold.

Those that fail to adapt to the cold conditions shall face extinction by being overpowered by cold related complications.

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Nicotinic receptors utilize g-proteins to regulate the opening of ion channels.

Paraphin [41]

Answer:

Correct option is (B) False.

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3 years ago

In an effort to reduce the United States' dependency on foreign oil, exploration and drilling throughout areas of the United Sta

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4 years ago

The movement of molecules down a concentration gradient through transport proteins in the cell membrane is a type of

ioda

Answer:

Facilitated Diffusion

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3 years ago

What is the term for a localized group of organisms belonging to the same species?

77julia77 [94]

Answer:

c. population

Explanation:

A localised group of organisms that belong to the same species is called Population. This can be a local population if the organisms stay at a particular place or a metapopulation if the organisms tend to move from one geographical location to another.

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2 years ago

Which statement describes potassium-argon dating?

Fiesta28 [93]

Answer: Potassium-40 decays into argon gas over time.

Explanation: Potassium-argon dating is a dating method used to determine the age of sedimentary rocks by comparing the proportion of K-40 to Ar-40 in a sample of rock, and knowing the decay rate of K-40.

Potassium-40 undergoes decay following first order kinetics as given below:

$_{19}^{40}\textrm{K}\rightarrow _{18}^{40}\textrm{Ar}+_{0}^1e$

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3 years ago

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